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Grace [21]
3 years ago
15

What is 3y+5x=-15 in slope-intercept form?

Mathematics
2 answers:
Sphinxa [80]3 years ago
4 0

3y + 5x = -15

3y = -5x - 15 (Subtract 5x from both sides)

y = -5/3x - 5 (Divide everything by 3)

Brums [2.3K]3 years ago
4 0

Answer: y = -5/3x - 5

Step-by-step explanation:

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(15) 3 (16) -0.6 (17) -2
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Y = sin (x + 60°), What transformation does + 60° cause to the sine graph?
Goshia [24]

Answer:

3. There is a phase shift (Horizontal shift).

Step-by-step explanation:

Use desmos to help you

Graph

y=sin(x+60)

y=sin(x)

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3 years ago
Distributive Property
algol13
1. 4 (6 + 7) is the same as (4 • 6) + (4 • 7)
    X = 4
2. 6 • 45 = 270
a. 270, (6 • 40) + (6 • 5) = 240 + 30 = 270
b. 210, (6 • 40) - (6 • 5) = 240 - 30 = 210
c. 270, (6 • 50) - (6 • 5) = 300 - 30 = 270
    A. 270, C. 270
3. 6m + 7n + 5m - 3n, combine like terms, 6m + 5m = 11m, 7n - 3n = 4n
    B. 11m + 4n
4. 2y<u>^3</u> - 4y^2 + y + y<u>^3</u>, exponents tell you what are like terms
    C. 2y^3 and y^3
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4 0
3 years ago
Please help, there’s a picture.
tino4ka555 [31]

Answer: zxy=39 wxy=78

Step-by-step explanation:

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6 0
3 years ago
Help me do this …math
Daniel [21]

Step-by-step explanation:

How to find inverse function:

Step 1: Write down equation.

f(x) = 4 \sin(x)  + 3

Remeber Ruler notation that

f(x)=y so we replace y with f(x).

y = 4 \sin(x)  + 3

Next, we must isolate x so first we subtract 3.

y - 3 = 4 \sin(x)

Divide both sides by 4.

\frac{y - 3}{4}  =  \sin(x)

\sin {}^{ - 1} ( \frac{y - 3}{4} )  =  \sin {}^{ - 1} ( \sin(x) )

Remeber that sin^-1x and sin x are inverse functions so they will cancel out to x. So we get

\sin {}^{ - 1} ( \frac{y - 3}{4} )  = x

Swap x and y. So our inverse function is

\sin {}^{ - 1} ( \frac{x - 3}{4} )  = y

If you want another proof: Here's one,

Let plug an a x value for the orginal equation,

4 sin x+3. Let say that

x =  \frac{\pi}{2}

We then would get

4 \sin( \frac{\pi}{2 } )  + 3 = 4 \times (1) + 3 = 4 + 3 = 7

So when x=pi/2, y=7.

By definition of a inverse function, if we let 7 be our input, we should get pi/2. as a output.

So let see.

\sin {}^{ - 1} ( \frac{7 - 3}{4} )  =  \sin {}^{ - 1} ( \frac{4}{4} )  =  \sin {}^{ - 1} (1)  =  \frac{\pi}{2}

So this is the inverse function of 4 sin x+3.

1b. The range of f(x) is [-1,7).

We can use transformations to describe range.

We have

f(x) = 4 \sin(x)  + 3

Parent function is

\sin(x)

with a range of [-1,1].

We then vertical stretch by 4 so we get

4 \sin(x)

and our range will be

[-4,4].

Then we add a vertical shift of 3.

4 \sin(x)  + 3

So our range of 4 sin x+3.

[-1,7].

1c. Domain of a inverse function is the range of the orginal function.

The range of f(x) is [-1,7) so the domain of f^-1(x) is [-1,7].

f(x) domain was restricted to -pi/2 to pi/2 so the range of f^-1(x) is [-pi/2, pi/2]

6 0
2 years ago
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