Given isosceles AHIJ where HIIT, MZH = (3x + 10)", and mZ1 = (6x – 20)", find the measures of angles H, I and J.
1 answer:
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Answer:
7.07
Step-by-step explanation:
<h2><u>Length</u></h2>a square has equal length on each side
hence is the perimeter is 20 it means that :
each side is 20/4 = 5
we can make a diagonal line which create 3 right angled triangles
2 sides of the triangle are 5 , this is the base and the height
to find the length we can make use of the Pythagoras theorem
c^2 = a^2 + b^2
c is the hypotenuse ( the diagonal;)
a and b are the opposite and adjacent
hence :
c^2 = 5 ^2 + 5^2
c^2 = 50
c =
c = 7.071
to 3sf
<h3><u>diagonal length = 7.07</u></h3>