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3 years ago

12

PLZ HURRY IT'S URGENT!!

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

x>-2 and x<1

Step-by-step explanation:

$-6$

Now dividing by 4:

$-2$

So, x is the value between -2 and 1, i.e. x has to be greater than -2 and smaller than 1

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At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion ring

andre [41]

Answer:

The number of onion rings is <u>3</u> in the combination meal and the number of sliders is <u>2</u> in the combination meal.

Step-by-step explanation:

Given:

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion rings and sliders has a total of 5 onion rings and sliders altogether and contains 695 calories.

Now, to find the number of onion rings in the combination meal and the number of sliders in the combination meal.

Let the number of onion rings in the combination meal be $x.$

And let the number of sliders in the combination meal be $y.$

<u><em>So, the total number of onion rings and sliders are:</em></u>

$x+y=5\\\\y=5-x\ \ \ .....(1)$

Now, the total number of calories each onion rings and sliders has:

$x(65)+y(250)=695$

Substituting the value of $y$ from equation (1) we get:

<em /> $x(65)+(5-x)(250)=695\\\\65x+1250-250x=695\\\\1250-185x=695$ <em />

<em>Subtracting both sides by 1250 we get:</em>

<em /> $-185x=-555$ <em />

<em>Dividing both sides by -185 we get:</em>

$x=3.$

<u><em>The number of onion rings in the combination meal = 3.</em></u>

Now, substituting the value of $x$ in equation (1) we get:

$y=5-x\\\\y=5-3\\\\y=2.$

<u><em>The number of sliders in the combination meal = 2.</em></u>

Hence, the number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

8 0

3 years ago

A parking lot has two entrances. Cars arrive at Entrance 1 according to a Poisson Probability Distribution at an average of thre

dusya [7]

Answer:

<u><em>note:</em></u>

<u><em>please find the attached solution</em></u>

7 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Find the linearization L(x) of the function at a. f(x) = x^4 + 2x^2, a = 1

gregori [183]

The equation of the tangent line at x=1 can be written in point-slope form as

... L(x) = f'(1)(x -1) +f(1)

The derivative is ...

... f'(x) = 4x^3 +4x

so the slope of the tangent line is f'(1) = 4+4 = 8.

The value of the function at x=1 is

... f(1) = 1^4 +2·1^2 = 3

So, your linearization is ...

... L(x) = 8(x -1) +3

or

... L(x) = 8x -5

8 0

3 years ago

Write the standard equation of the circle if the center is (-1,2), and a point on the circle is (2,6).

ladessa [460]

Answer:

(x + 1)² + (y - 2)² = 25

Step-by-step explanation:

<u>The center is given:</u>

(-1, 2)

<u>Find the radius, the distance from the center to a point (2, 6)</u>

r² = (2 - (-1))² + (6 - 2)² = 3² + 4² = 25
r = √25 = 5

<u>Use circle formula:</u>

(x - h)² + (y - k)² = r²
(x - (-1))² + (y - 2)² = 5²
(x + 1)² + (y - 2)² = 25

8 0

3 years ago

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