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3 years ago

Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.

Mathematics

1 answer:

Kobotan [32]3 years ago

7 0

$h = \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}$

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Doss [256]

I think your answer is 90

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3 years ago

How many pounds of walnuts that cost $6.50 per pound must be mixed with 7 pounds of cashews that cost $11 per pound to make a mi

AveGali [126]

Answer:You will need to buy 1/2 a pound of cashews and 1/2 a pound of peanuts

3 0

3 years ago

Which expressions are equivalent to 2(l + w)?

Sergio [31]

Answer:I think it’s 52

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Needed help with this question!

In-s [12.5K]

A) is 2x
b) is $x^{3}$
c) is -2x

I think these are correct.
$log_{10}1000^{x] = log_{10}10^{2x}=2x$
I did similar things to get other answers
$1000^{log_{10}x} = 10^{3log_{10}x}=10^{log_{10}x^{3}}=x^{3}$

5 0

3 years ago

Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.

Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

the points will be clustered according to their distance to the centroids.
Then centroids are updated as the cluster means.
This process continues until clusters doesn't change anymore

1) initial centroids 10-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

new centroids 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

final centroids 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = $(18-6)^{2}$ + $(18-12)^{2}$ + $(18-18)^{2}$ + $(18-24)^{2}$ + $(18-30)^{2}$ + $(45-42)^{2}$ + $(45-48)^{2}$ =378

2)initial centroids 10-20

first cluster (6,12) mean:9

second cluster (18,24,30,42,48) mean:32.4

new centroids 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

new centroids 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

final centroids 15-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

Sum of Squared errors = $(15-6)^{2}$ + $(15-12)^{2}$ + $(15-18)^{2}$ + $(15-24)^{2}$ + $(40-30)^{2}$ + $(40-42)^{2}$ + $(40-48)^{2}$ =348

6 0

4 years ago