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Paladinen [302]
3 years ago
8

Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0
h =  \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}
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Answer:

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Step-by-step explanation:

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Find the circumference of a circle whose area is 24
zalisa [80]

The answer is: " 17.35 " .

__________________________________

→ The circumference of the circle is: " 17.35 units " .

__________________________________


The area, "A", of a circle:

A = \pi * r² ;

Note: \pi  = 3.14 .

The area of the circumference, "C", of a circle:

C = 2 \pi r .

__________________________________________

Given:

A = 24 ;

Use the formula for the area, "A" of a circle, to find the radius, "r" .

Then, plug the value obtained for "r" into the formula for the circumference, "C" , of a circle:

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To solve for the circumference, "C", of the circle.

________________

A = \pi  *  r^{2} ;

24 = 3.14 * r² ;

↔ 3.14 * r² = 24 ;

Divide each side of the equation by "(3.14)" ;

[3.14 * r²] / 3.14 = (24) / (3.14) ;

to get:

→ r² = 7.64331210191 ;

Take the positive square root of each side of the equation;

to isolate "r" on one side of the equation; & to solve for the radius, "r" ;

→ ⁺√(r²) = ⁺√(7.64331210191) ;

to get:

→ r = 2.76281034802 ;

____________________________

Now, plug this "obtained value" for the radius, "r" into the equation for the formula for the circumference, "C" of a circle:

→ C = 2 \pi * r ;

to solve for the circumference, "C", of the circle:

→ C = 2 * (3.14) * (2.76281034802) ;

= (6.28) * (2.76281034802) ;

= 17.3504489856 ;

→ round to: " 17.35 units" .

__________________________________

The answer is: " 17.35 " .

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→ The circumference of the circle is: " 17.35 units " .

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Step-by-step explanation:

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