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Paladinen [302]
3 years ago
8

Find the length of the hypotenuse of an isosceles right triangle whose legs are 1 unit in length.

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0
h =  \sqrt{ 1^{2} + 1^{2} } = \sqrt{1+1} = \sqrt{2}
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The base of a rectangular solid is 4ft. long and 3ft. wide. What is the volume of the solid if its diagonal is sqrt of 41 ft.?
geniusboy [140]
The diagonal of the figure forms a right angle triangle with the diagonal of the base and the height of the figure.
Diagonal of base = √(3² + 4²)
= 5ft
Diagonal of solid² = Diagonal of base² + height²
height = √((√41)² + 5²)
height = 8.12 feet
Volume = width x length x height
Volume = 3 x 4 x 8.12
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Step-by-step explanation:

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Shane biked 1 mile less than three times the number of miles Lissette biked. Shane biked a total of 7 miles. Write an equation t
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The equation of the line passing through the points (3, 16) and (5, 10) can be expressed as y = mx + b. Give the value of b
Alenkinab [10]

we are given two points as

(3, 16) and (5, 10)

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so, we can use formula

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now, we can plug points

m=\frac{10-16}{5-3}

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we can plug it in y=mx+b

we get

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now, we can select any one points

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(3,16)

x=3 and y=16

16=-3*3+b

we can find b

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y=-3x+25

so, equation is

y=-3x+25

and

b=25...............Answer

8 0
3 years ago
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