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sashaice [31]
3 years ago
15

Which number is greatest? ооо 6.23 х 1012 6.23x 108 Б.23 х 10- o 6.23x 103

Mathematics
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

Option A: 6.23 x 1012

Step-by-step explanation:

Please check provided image.

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Bag contains 4 red marbles, 2 blue marbles, 1 purple
GaryK [48]

Answer:

432

Step-by-step explanation:

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2 years ago
Simplify the problem 2/sqrt 5
AURORKA [14]
2/sqrt 5

by rationalising the denominator,

2/sqrt 5 × sqrt 5/sqrt 5

= 2(sqrt 5)/sqrt 5(sqrt 5)

= 2 sqrt 5/5

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7 0
3 years ago
839<br><img src="https://tex.z-dn.net/?f=839%20%5Cdiv%2041" id="TexFormula1" title="839 \div 41" alt="839 \div 41" align="absmid
goldfiish [28.3K]

Answer:

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Step-by-step explanation:

839/41=20.4634146341

6 0
2 years ago
A sign in the the store window advertises 3-t shirts for $16.50 which coronet pierced as a unit rate of the T-shirt sale sc $16.
Kruka [31]
You would have to divide 16.50 into 3 then put your answer down hope this helps
8 0
3 years ago
The average student-loan debt is reported to be $25,235. A student believes that the student-loan debt is higher in her area. Sh
yulyashka [42]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 25235

For the alternative hypothesis,

µ > 25235

This is a right tailed test.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 100,

Degrees of freedom, df = n - 1 = 100 - 1 = 99

t = (x - µ)/(s/√n)

Where

x = sample mean = 27524

µ = population mean = 25235

s = samples standard deviation = 6000

t = (27524 - 25235)/(6000/√100) = 3.815

We would determine the p value using the t test calculator. It becomes

p = 0.000119

Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.

6 0
3 years ago
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