6 years ago jack was three times older then wade. In four years wade will be half as old as jack. How old are they now?

Mathematics

1 answer:

mixer [17]4 years ago

4 0

Answer:

Jack's age is 36

Wade's age is 16

Step-by-step explanation:

Let jack's age be "j"

and

Wade's age be "w"

First, we have:

6 yrs AGO, Jack was 3 times as Wade, so we can write:

j-6 = 3(w-6)

Then, we have:

4 yrs from NOW, Wade will be HALF as Jack, so we can write:

w+4 = 0.5(j+4)

Lets simplify the first equation:

j-6 = 3(w-6)

j - 6 = 3w - 18

Solving for j:

j = 3w - 18 + 6

j = 3w - 12

Now, simplifying the second equation:

w+4 = 0.5(j+4)

w+4 = 0.5j+2

w = 0.5j - 2

Now we replace this equation with j's expression we found from first equation:

w = 0.5j - 2

w = 0.5(3w - 12) - 2

w = 1.5w - 6 - 2

0.5w = 8

w = 16

Now, finding j:

j = 3w - 12

j = 3(16) - 12

j = 36

So,

Jack's age is 36

Wade's age is 16

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In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is $A=\pi r^2$ where r is the radius.
$A=\pi (4)^2=\pi (4\times4)=16\pi=B$

We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.

$V=\frac{1}3\times16\pi \times9$

Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.

$V\approx\frac{1}3\times50.24\times9$

We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.

$V\approx3\times50.24$

$\boxed{V\approx150.72\ cm^3}$