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Darya [45]
4 years ago
5

Enter the simplified version of the expression

Mathematics
1 answer:
lilavasa [31]4 years ago
3 0
657 because it is answer
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HHHHHHHHHHHHHEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLPP
Naya [18.7K]

Answer:

the 1st answer is H, yw

Step-by-step explanation:

quadrant I is on the top right, quadrant II is on the upper left, quadrant III is on the bottom left, and quadrant IV is on the bottom right. H is located in the top left (quadrant 2)

7 0
3 years ago
a store sells small notebooks for $8 and a large notebook for $10.if a student buys 6 notebooks and spends $56,how many of each
GalinKa [24]
He bought 4 large ($10) and 2 small ($8)
8 0
3 years ago
Read 2 more answers
34. The diagram shows a sector of a circle of radius 10 cm.
Sergio [31]

Answer:

rc  length  =  10 * 8pi/5

 =   16pi

This is the circumference of the base

(a)   2pir     =   16pi  where  r  =  radius of base

  2r     =    16

   r     =  8 cm

(b)   10^2    =   h^2   +  8^2

 h^2    =   100  -  64

  =    36

h      =    6 cm

8 0
3 years ago
Read 2 more answers
There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
Help me. I don't get it :(
sukhopar [10]
10) because of the alternative exterior angle theorem angle 2 is the same as angle 8 and because of the vertical angles congruence theorem angles 2 and 4 are also the same so if angle 2 is the same as both 4 and 8,
then x=5 because 4x+57 =77
subtract 57 from both sides and 4x=20
divide both sides by 4 and x equals 5
5 0
3 years ago
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