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murzikaleks [220]
3 years ago
6

5. A cube is a three-dimensional solid with six square faces.

Mathematics
1 answer:
Bond [772]3 years ago
6 0
Conditionallslslslod
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Select the correct answer. If f(x) = |x| - 4, which translation is applied fo f(x) to get g(x)?
solmaris [256]

Answer:

It is a vertical translation of f(x) four units downward.

Step-by-step explanation:

We are given the original equation f(x) = |x| and the transformed function is g(x) = |x| - 4.

It is clear that the transformed function that g(x) = f(x) - 4.

So, the y-value in g(x) is reduced by 4 units from the y-value of f(x) i.e. the transformation is by 4 units down of function f(x).

Therefore, it is a vertical translation of f(x) four units downward. (Answer)

8 0
3 years ago
Everett made 3/5 of the baskets he shot suppose he shot 60 baskets how many did you make
lions [1.4K]
He made 36 baskets I think
3 0
3 years ago
Read 2 more answers
Given the functions below, find (f - g) (2).<br> f(x)<br> x2 + 3<br> g(x) = 4x – 3<br> =
kakasveta [241]

Answer:

(f - g)(2) = 2

Step-by-step explanation:

Given the functions below, find (f - g) (2).

f(x) = x² + 3

g(x) = 4x – 3

(f - g)(x) = (x²+3)-(4x-3)

(f - g)(x) = x²+3-4x+3

(f - g)(x) = x²-4x+6

(f - g)(2) = (2)²-4(2)+6

(f - g)(2) = 4-8+6

(f - g)(2) = 2

5 0
3 years ago
Which is the graph of f(x) = –(x + 3)(x + 1)
Sergio [31]

Answer: Please refer to the attachment below

Step-by-step explanation:

4 0
3 years ago
Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0
Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: x^4+9x^2-4x^2-36

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: x^2(x^2+9)-4(x^2+9)

Now you can rewrite this as (x^2-4)(x^2+9) , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is a^2-b^2=(a+b)(a-b) . Applying that here, we have (x+2)(x-2)(x^2+9) . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 2x^2+10x-x-5

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 2x(x+5)-1(x+5)

Now you can rewrite the equation as (2x-1)(x+5) . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is (x+2)(x-2)(x^2+9)(2x-1)(x+5)=0</u></h3>
5 0
3 years ago
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