Since
The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have
![\begin{array}{c|c}n&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dn%26n%5E2%5C%5C3%269%5C%5C3.1%269.61%5C%5C3.2%2610.24%5C%5C3.3%2610.89%5C%5C3.4%2611.56%5Cend%7Barray%7D%5Cright%5D)
So, the square root of 11 is somewhere between 3.3 and 3.4.
The answer would be A. He doesn't acknowledge the power of nature. He believes that he has more time and resources but of course, this was not the case and the cold had overtaken him.
Answer:
-3
Step-by-step explanation:
using pemdas, we first divide -18 by 6 to get -3. next, we subtract -3 from -6: -6-(-3)=-6+3=-3
Answer:
x= 7
x=6
Step-by-step explanation:
5+2x=19
Subtract 5 from both sides
so...
2x=14
then divide by two to isolate the x
so..
x=7
4x+3=27
Subtract 3 from both sides
so...
4x=24
then divide by 4 to isolate the x
so....
x=6
Answer:
what
Step-by-step explanation:
