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balu736 [363]
2 years ago
12

Determine the lengths a and b given the following information. B=14.5° c=6°"​

Mathematics
1 answer:
mario62 [17]2 years ago
5 0

Answer:

The answer might be B

Step-by-step explanation:

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Joe runs 8.25 times around a track in 1,119.803 seconds. If one lap around the track is 402.3 meters, which is the best estimate
alexgriva [62]
2.96 meters per second is the answer I'm getting. I took the total seconds and divided it by how many times he ran around the track to get his speed for lap and then I divided his lap speed by how long the track was to get his meters per second
5 0
3 years ago
Consider the following hypothesis test H0 p 20 Ha p 20 A sample of 400 provided a sample proportion p 175 a Compute the value of
Bogdan [553]

Answer:

a) -1.25

b) 0.2112

c) -1.96

Step-by-step explanation:

Data provided in the question:

Sample size, n = 400

H0 : p = 20

\bar{p} = 175

Now,

a) The test statistic is  given as:

Z = \frac{(\bar{p}-p)}{\sqrt{\frac{p(1-p)}{n}}}

on substituting the respective values, we get

Z = \frac{(0.175-0.2)}{\sqrt{\frac{0.2\times0.8}{400}}}

= -1.25

b) The p-value = 2 × P(Z <-1.25)

Now from the standard normal table

P(Z <-1.25) = 10.56% = 0.1056

Thus,

p-value = 2 × 1056 = 0.2112

c) for a = 0.05,

the critical value is Z_{\frac{a}{2}}=Z_{\frac{0.05}{2}} i.e Z_{0.025}

Now from standard normal table

Z_{0.025} = -1.96

3 0
3 years ago
The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area
Anna [14]

Answer:

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

Area=length\times width

Area of rectangle B is

A_B=l\times w

The area of rectangle B is 162 square cm.

A_B=l\times w=162

Area of rectangle A is

A_A=4l\times 4w=16(l\times w)=16(162)=2592

Therefore, the area of rectangle A is 2,592 square cm.

3 0
3 years ago
0 write the quation of the<br> graph
Vika [28.1K]

to get the equation of any straight line, all we need is two points from it, Check the picture below, let's use those two.

(\stackrel{x_1}{-5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{1+5}{0+5}\implies \cfrac{6}{5}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{\cfrac{6}{5}}(x-\stackrel{x_1}{(-5)}) \\\\\\ y+5=\cfrac{6}{5}(x+5)\implies y+5=\cfrac{6}{5}x+6\implies y=\cfrac{6}{5}x+1

8 0
2 years ago
Consider the probability that more than 87 out of 155 students will pass their college placement exams. Assume the probability t
Helen [10]

the probability that more than 87 students will pass their college placement exam is 0.9616.

5 0
3 years ago
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