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Sonja [21]
4 years ago
7

Compare the functions shown below in the attachment:

Mathematics
1 answer:
liubo4ka [24]4 years ago
3 0
In a graph, "y" axis is the vertical axis and the blue curve is your function "f(x)". So, on the blue curve, trace and mark the place that is the highest in the given window. Notice that when "x" axis (the horizontal one) is π, the blue curve reaches its highest point,
For <span>h(x)=2cos(x)+1</span>, remember that the maximum value for <span>cos(x)</span> is "1". So, the maximum value for<span>h(x)=2(1)+1<span>=3</span></span>
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The cost (in dollars) of making b bracelets is represented by 4 5b. The cost (in dollars) of making b necklaces is represented b
Leviafan [203]

Answer:

$(3b+2)

Step-by-step explanation:

The cost of making b bracelets = 4+5b

The cost  of making b necklaces = 8b+6.

To determine how much more it cost to make b necklaces than b bracelets, we simply subtract.

Extra Cost = Cost of b Necklaces-Cost of b Bracelets

=(8b+6)-(4+5b)

open the brackets

=8b+6-4-5b

Collect like terms

=8b-5b+6-4

=3b+2

It costs $(3b+2) more to make b necklaces than b bracelets.

3 0
4 years ago
Solve for x.<br> 2.8 3.2x + 1 = 16.6
Yuliya22 [10]

Answer:

\sf x = \dfrac{15.6-2.8a}{3.2}

Step-by-step explanation:

Solve for 'x'.

To solve for 'x', isolate 'x'.

 2.8a + 3.2x + 1 = 16.6

Subtract 1 from both sides.  {Subtraction property of equality}

   2.8a + 3.2x = 16.6 - 1

    2.8a + 3.2x = 15.6

Subtract 2.8 a from both sides.

              3.2x  = 15.6 - 2.8a

Now, divide both sides by 3.2.  {Division property of equality}

                 \sf \dfrac{3.2x}{3.2}=\dfrac{15.6-2.8a}{3.2}\\\\\boxed{x=\dfrac{15.6-2.8a}{3.2}}

                 

6 0
2 years ago
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
4 years ago
Point T is on line segment SU. Given SU = 17 and TU<br> length ST<br> 14, determine the
ki77a [65]

Answer:17

Step-by-step explanation:

3 0
3 years ago
Which expression is a factor of 21 x2 + 13 x-20
Nesterboy [21]

Answer:

(7x−5)(3x+4)

Step-by-step explanation:

I think this is the answer

6 0
3 years ago
Read 2 more answers
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