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2 years ago

I need help. someone help please!

Mathematics

2 answers:

Vikentia [17]2 years ago

4 0

Sorry, I think there is missing context?

yanalaym [24]2 years ago

3 0

Answer:

Step-by-step explanation:

The rule governing the number of magazines sold varies directly with the constant of proportion 10:

10 times the number of students comes out to 100: 10(10) = 100

25 times the number of students comes out to 250: 10(25) = 250

and so on.

In summary: the number of magazines sold is y = 10x, where x is the number of students involved.

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Work out the area of the shaded shape.

CaHeK987 [17]

The answer would be 61m^2

5x11=55
8-5=3
11-9=2
2x3=6
6+55=61

and since it is the area it is squared
hope this helps

5 0

2 years ago

Solve the following quadratic equation for its exact value by using the square root principle.

Korvikt [17]

Idk what the hell all that is but x = 1.802775637731995

4x^2 - 13 = 0

4x^2 = 13

13/4=3.25

x^2 = 3.25

x = ~1.8

5 0

3 years ago

A display that uses bars to show data is an

Vika [28.1K]

Histogram
A histogram is a graphic display of quantitative variables that uses bars to represent the frequency of the count of the data in each interval. A boxplot is a graphic display of quantitative data that demonstrates the five-number summary.

6 0

2 years ago

A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a

BigorU [14]

Answer:

$R'(20) = 2000$

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

$q=f(p)$

Total revenue earned =

$R(p)=pf(p)$

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

$R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)$

Putting the values, we get,

$R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000$

7 0

3 years ago

Help me on this one please hellppp

katrin [286]

Answer:

smh-

Step-by-step explanation:

6 0

2 years ago