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Dominik [7]
3 years ago
7

Solve each expression 2n^2+3n-2

Mathematics
2 answers:
Gnom [1K]3 years ago
5 0
Simple, solve straight across, its either 4n or 2n
dangina [55]3 years ago
5 0
<span><span> n = -1/2 = -0.500
</span><span> n = 2
I ended up with these two answers </span></span>
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2z -5(z +2) = -8 - 2z<br><br> Please explain!! Thank you
Korolek [52]

Follow PEMDAS.

You would first do your distributive property which is, -5(z+2). You would multiply -5 to z and -5 to 2 which will give you -5z + -10.

so now you have 2z-5z+ -10= -8 - 2z. Now you must isolate the variable. So subtract -8 to -10 which will give you -18.

Now you have the equation 2z-5z-18=-2z

Now combine like terms. 2z-5z= -3z

Now you have the equation -3z-18=-2z

Now you must move the -3z to the other side of the equal sign by adding the opposite which is +3z to -2z which will give you +1z

Now you have -18= 1z

Now you divide. -18 divided by 1 is -18.

So your final answer will be -18=z

7 0
3 years ago
Using the equation y = 3x – 5, what would the output be for an input of 4
SSSSS [86.1K]
The input is the x-coordinate and the output is the y-coordinate. If the input is 4, plug 4 into the x variable to find the output, y.

y=3(4)-5
y=12-5
y=7

The output is 7.
8 0
3 years ago
Read 2 more answers
Two planes that do not intersect are parallel
frez [133]

True.  If they never intersect then they must have the same slope and are parallel

6 0
3 years ago
Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
4 years ago
Grandma has 14 red roses and 7 pink roses. How many more red roses than pink roses she have?
Tanzania [10]
7. 14-7=7/ 7+7= 14.
3 0
3 years ago
Read 2 more answers
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