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uranmaximum [27]
2 years ago
5

Question 28 of

Mathematics
1 answer:
Helen [10]2 years ago
7 0

y - y1 = m(x - x1) \\ y - 8 = 15(x - 2) \\ y - 8 = 15x - 30 \\ y = 15x - 30 + 8 \\ y = 15x - 22

The equation of line is y = mx+b ; m is slope , b is y- intercept

Please give brainlest

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67.5 into a fraction
andrey2020 [161]

Answer:

67 1/2

Step-by-step explanation:

67 5/10

67 1/2

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3 years ago
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7y = 14 -28x to standard form
MissTica

Answer:

28x + 7y = 14.

Step-by-step explanation:

Just add the 28x to each side.

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3 years ago
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How many digits are in the repetend of the decimal expansion for 2/41
AleksandrR [38]

Answer:

0.0487804878

Step-by-step explanation:

the answer will be 5 because it starts at 0.

5 0
2 years ago
Four friends bought 2 pizzas and 4 large soft drinks. They shared the cost equally. Each pizza cost
valina [46]

Answer:

$7.85

Step-by-step explanation:

2 pizzas at 11.99=23.98

4 soft drinks at 1.85=$7.40

23.98+7.40=31.38

31.38/4=7.845

Each friend pays $7.845, or $7.85 .........

7 0
2 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
3 years ago
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