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uranmaximum [27]
1 year ago
5

Question 28 of

Mathematics
1 answer:
Helen [10]1 year ago
7 0

y - y1 = m(x - x1) \\ y - 8 = 15(x - 2) \\ y - 8 = 15x - 30 \\ y = 15x - 30 + 8 \\ y = 15x - 22

The equation of line is y = mx+b ; m is slope , b is y- intercept

Please give brainlest

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Write a linear equation that passes through the points(2,-2) and (0,1)
Yakvenalex [24]

Answer:

Slope intercept: y = -3/2x + 1

Point slope: y + 2 = -3/2 * (x - 2) [Forgot to add the work for this, I will add it if you need it, feel free to ask.]

Step-by-step explanation:

m = (change in y)/change in x)

But also

m = y_2 - y_1/x_2 - x_1


So lets substitute

m = 1 - (-2)/0 - (2)

Lets find the slope

m = 3/0 - (2)

m = 3/-2

m = -3/2 (Moved the negative)

Now we find the value of b using the equation of a line.

y = mx + b

y = (-3/2) * x + b

y = (-3/2) * (2) + b

-2 = (-3/2) * (2) + b

Now we find the value of b

Lets rewrite

-3/2 * 2 + b = -2

Cancel the CF of 2

-3 + b = -2

Move the terms without b to the right

b = -2 + 3

b = 1

Now we substitute our values of the slope and y-int into y = mx + b to find the equation.

y = -3/2x + 1

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Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

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