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Shalnov [3]
3 years ago
6

Write 0.16666 as a fraction

Mathematics
2 answers:
AVprozaik [17]3 years ago
5 0
The answer to this specific question which is “Write 0.16666 as a fraction.” Is 1/6
olchik [2.2K]3 years ago
4 0

This one you can do by multiplying the number by ten, getting 1.666, or 1+0.66. 0.66 is easy to put into a fraction form as 2/3. add the other 3/3 from the whole 1 to get 5/3. From here you either divide by 10 or multiply by 1/10, as KCF will do that anyways if you divide to get 5/30, or 1/6.

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The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

6 0
3 years ago
The areas of the squares adjacent to two sides of a right triangle are 32units^2 and 32 units^2
adoni [48]

Answer:

x = 8 units.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>

My answer:

  • Let a is the side length of the 1st square

The area of the 1st square is equal to 32 units square

<=> a^{2} = 32

<=> a = 4\sqrt{2} units

  • Let b is the length  of the 2nd  square

The area of the 2nd square is equal to 32 units square

<=> b^{2} = 32

<=> b = 4\sqrt{2} units

  • Find the value of x

Applying the Pythagoras Theorem, we have:

x^{2} = a^{2} + b^{2}

<=> x^{2}  = 32 + 32  

<=> x^{2} = 64

<=> x = 8 units

Hope it will find you well.

4 0
3 years ago
Read 2 more answers
Which inequality has the solution shown below?
salantis [7]

Answer: Where inequality?

Step-by-step explanation:

5 0
3 years ago
Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a  = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

4 0
3 years ago
Evaluate 3^-2 mathswatch hw ahhahahhahahahahhahaha
Andru [333]

Answer:

1/9

Step-by-step explanation:

3^-2

0.111111...

1/9

8 0
4 years ago
Read 2 more answers
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