Determine the quadrant adding or subtracting periods -10pi/3+2pi=-4pi/3+2pi=2pi/3
which is the second quadrant because
first quadrant is between 0 and pi/2
second quadrant is between pi/2 and pi
third quadrant is between pi and 3pi/2
fourth is between 3pi/2 and 2pi
now we find the terminal angle since it is the second quadrant we use theta'=pi-theta=pi-2pi/3=pi/3
sin(pi/3)=sqrt(3)/2 sin is positive in the second quadrant
cos(pi/3)=-0.5 cos is negative in the second quadrant
tan(pi/3)=sin(pi/3)/cos(pi/3)=-sqrt(3) tan is negative in the second quadrant
Answer:
6 meters
Step-by-step explanation:
The sum of the lengths of any two sides of a triangle is always greater than the length of the third side. And this MUST be true for all the combinations
The only length where this is true is 6
3+5 is greater than 6
2+6 is greater than 5
5+6 is greater than 3
The answer is D. 3x^3+4x^2-11x+3
