The critical angle is the angle of incident in the optically dense media that produces the angle of refraction as 90°.
sin c =1/n, where n is the refractive index and c is the critical angle.
Also, n1sinФ1=n2sinФ2
In this case we have,
1.33×sinc = 1.309×sin90° Where c is the critical angle.
sin c =1.309/1.33
sin c = 0.981995498
c = 79.11°
Answer:
E = 7.70 × 10⁻²⁸ J
Explanation:
Energy = hf
h = Planck's constant = 6.63 × 10⁻³⁴ J.s
f = frequency = 1160 KHz = 1.16 × 10⁶ Hz
E = (6.63 × 10⁻³⁴ × 1.16 × 10⁶)
E = 7.70 × 10⁻²⁸ J
Answer:
option D
Explanation:
given,
mass of the freight car (m) = 5,000 Kg
initial speed of car (u)= 2 m/s
mass of the freight car (M)= 10,000 Kg
initial speed (u')= 0 m/s
speed after collision (V)= ?
using conservation of momentum
m u + M u' = (M + m) V
5000 x 2 + 10000 x 0 = (5000 + 10000) V
couples move away with the speed of
Hence, the correct answer is option D
If the amplitude of the wave increases by 4 times, the intensity will increase by 16 times. Option B is correct.
<h3 /><h3>What is the relation between the
intensity and the
Amplitude?</h3>
The intensity is directly proportional to the square of the amplitude of the wave.
Where,
- Intensity
- Amplitude
- constant
Thus, if the amplitude of the wave increased by 4 times,
Therefore, if the amplitude of the wave increases by 4 times, the intensity will increase by 16 times.
Learn more about amplitude
brainly.com/question/3539752
Answer:
29.0 g
Explanation:
The mass of the piece of gold is given by:
m = dV
where
m is the mass
d is the density
V is the volume of the piece of gold
The density of gold is
d = 19.3 g/cm^3
while the volume of the sample is equal to the volume of displaced water, so
V = 64.5 mL - 63.0 mL = 1.5 mL
And since
1 mL = 1 cm^3
the volume is
V = 1.5 cm^3
So the mass of the piece of gold is:
m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g