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alexdok [17]
3 years ago
8

A graduated cylinder contains 63.0 mL of water. A piece of gold, which has a density of 19.3 g/ cm3, is added to the water and t

he volume goes up to 64.5 mL. Calculate the mass in grams of the gold that was added to the water. Explain how you got your answer.
Physics
1 answer:
icang [17]3 years ago
7 0

Answer:

29.0 g

Explanation:

The mass of the piece of gold is given by:

m = dV

where

m is the mass

d is the density

V is the volume of the piece of gold

The density of gold is

d = 19.3 g/cm^3

while the volume of the sample is equal to the volume of displaced water, so

V = 64.5 mL - 63.0 mL = 1.5 mL

And since

1 mL = 1 cm^3

the volume is

V = 1.5 cm^3

So the mass of the piece of gold is:

m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g

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