A graduated cylinder contains 63.0 mL of water. A piece of gold, which has a density of 19.3 g/ cm3, is added to the water and t
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Answer:
R = 668.19 ft
Explanation:
given,
speed of the ball thrown by the pitcher = 100 mph
to travel maximum distance θ = 45°
distance traveled by the ball = ?
using formula
1 mph = 0.44704 m/s
100 mph = 44.704 m/s
R = 203.71 m
1 m = 3.28 ft
R = 203.71 × 3.28
R = 668.19 ft
hence, ball will go at a distance of 668.19 ft when pitcher throw it at 100 mph.
The magnetic field strength is 9.47 ×10⁻⁴ T
The energy density at the center of the loop is 0.36 J/m³
<h3>Calculating Magnetic field strength & Energy density </h3>From the question, we are to find the magnetic field strength
The magnetic field strength of a loop can be calculated by using the formula,
Where B is the magnetic field strength
is the permeability of free space
is the current
and R is the radius
From the give information,
and
Putting the parameters into the formula, we get
Hence, the magnetic field strength is 9.47 ×10⁻⁴ T
Now, for the energy density
Energy density can be calculated by using the formula,
Where is the energy density
Then,
Hence, the energy density at the center of the loop is 0.36 J/m³
Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557