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PIT_PIT [208]
3 years ago
12

Why is it important for you to understand the basics of organ systems?

Physics
1 answer:
marissa [1.9K]3 years ago
5 0
This question can have ALOT of answers but ill leave you with these summed up points and you can take what you need from it they are get right to the point! Sorry if they long paragraphs scare you lol




*You want to provide patients the best care possible. Most often your patients will have a disease. Diseases result when there is something abnormal in the anatomy and physiology of a structure. With a car, you can’t understand how to fix an engine if you don’t know how it works. The same is true with your patients. You can’t really understand how to treat them or why the treatment works, if you don’t understand how the effected body system normally functions.

*Patients will want to understand their diseases. In order to help them understand what is going wrong, you have to first understand how a particular organ is supposed to work. In addition, you will need to be able to explain these things to patients in a way that they can understand. If you don’t understand it well, you won’t be able to explain it. Your patient’s confidence in your ability will be at least partially determined by your ability to discuss what you are doing and why you are doing it. You will need to look up information if you are not sure.

*Organ systems are so interconnected that a disease in one system may result in a symptom in another system. Without seeing the normal interconnectedness, you cannot fully understand the disease.


*Success in an allied health field requires at least three things. First, you must have the personality to be able to support and help patients. Secondly, you must have the scientific and technical knowledge necessary to make the correct decisions regarding patient care. Thirdly, you must have the clinical skills necessary to implement this kno
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Which scientist discovered the laws that determine the motion of a spring?
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Answer: Robert Hooke

Explanation: Hooke's law, law of elasticity discovered by the English scientist Robert Hooke in 1660, which states that, for relatively small deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load.

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Two objects of the same mass travel in opposite directions along a horizontal surface. Object X has a speed of 5ms and object Y
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Answer:

1

Explanation:

Because theyre heading opposite directions

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3 years ago
Show that rigid body rotation near the Galactic center is consistent with a spherically symmetric mass distribution of constant
irakobra [83]

To solve this problem we will use the concepts related to gravitational acceleration and centripetal acceleration. The equality between these two forces that maintains the balance will allow to determine how the rigid body is consistent with a spherically symmetric mass distribution of constant density. Let's start with the gravitational acceleration of the Star, which is

a_g = \frac{GM}{R^2}

Here

M = \text{Mass inside the Orbit of the star}

R = \text{Orbital radius}

G = \text{Universal Gravitational Constant}

Mass inside the orbit in terms of Volume and Density is

M =V \rho

Where,

V = Volume

\rho =Density

Now considering the volume of the star as a Sphere we have

V = \frac{4}{3} \pi R^3

Replacing at the previous equation we have,

M = (\frac{4}{3}\pi R^3)\rho

Now replacing the mass at the gravitational acceleration formula we have that

a_g = \frac{G}{R^2}(\frac{4}{3}\pi R^3)\rho

a_g = \frac{4}{3} G\pi R\rho

For a rotating star, the centripetal acceleration is caused by this gravitational acceleration.  So centripetal acceleration of the star is

a_c = \frac{4}{3} G\pi R\rho

At the same time the general expression for the centripetal acceleration is

a_c = \frac{\Theta^2}{R}

Where \Theta is the orbital velocity

Using this expression in the left hand side of the equation we have that

\frac{\Theta^2}{R} = \frac{4}{3}G\pi \rho R^2

\Theta = (\frac{4}{3}G\pi \rho R^2)^{1/2}

\Theta = (\frac{4}{3}G\pi \rho)^{1/2}R

Considering the constant values we have that

\Theta = \text{Constant} \times R

\Theta \propto R

As the orbital velocity is proportional to the orbital radius, it shows the rigid body rotation of stars near the galactic center.

So the rigid-body rotation near the galactic center is consistent with a spherically symmetric mass distribution of constant density

6 0
3 years ago
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