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romanna [79]
4 years ago
11

Triangle ABC is transformed to triangle A′B′C′, as shown below:

Mathematics
1 answer:
aniked [119]4 years ago
7 0

Answer: Ok so theres no letter or number options to choose from but the answer is B. Hope this helps :)

Step-by-step explanation:

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Find a third-degree polynomial equation with rational coefficients that has roots –5 and 6 + i.
Vitek1552 [10]

The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+<em>i</em> is a root, so 6-<em>i</em> is also a root.

So the simplest polynomial you can build with these roots is

(<em>x</em> - (-5)) (<em>x</em> - (6 + <em>i </em>)) (<em>x</em> - (6 - <em>i</em> )) = <em>x</em> ^3 - 7<em>x</em> ^2 - 23<em>x</em> + 185

(first choice)

8 0
3 years ago
(02.02 LC)<br> If g(x) = x2 – 4, find g(5)
never [62]

g(5) means we substitute every x in the equation with a 5.

g(5) = (5)^2 - 4.

g(5) = 21.

4 0
4 years ago
Read 2 more answers
X² + y² = 8
ohaa [14]

Answer:

(2,2)~ \text{and}~ (-2,-2)

Step by step explanation:

x^2 +y^2 =8~~~~~~...(i)\\\\x-y=0~~~~~~~~~...(ii)\\\\\text{From (ii):}\\\\x-y = 0 \implies x = y\\\\\text{Substitute x = y  in eq (i):}\\\\~~~~~~y^2 +y^2 =8\\\\\implies 2y^2 = 8\\ \\\implies y^2 = \dfrac 82\\\\\implies y^2 = 4\\\\\implies y = \pm\sqrt 4\\\\\implies y = \pm 2\\\\\text{Substitute y = x  in equation (i):}\\ \\~~~~~~x^2 +x^2 = 8\\ \\\implies 2x^2 = 8\\\\\implies x^2 = \dfrac 82\\\\\implies x^2 = 4\\\\\implies x = \pm\sqrt 4\\\\\implies x = \pm2\\\\

\text{Hence,}~ (x,y) = (\pm2, \pm 2)

3 0
2 years ago
What value should go in the empty boxes to complete the calculation for finding the product of
Mars2501 [29]
The number is 6. 8*7=56, 9*7+5=68, 6860.
3 0
4 years ago
51-8; and v=
zhannawk [14.2K]

Answer:

  b.  98.5°

Step-by-step explanation:

There are a number of ways to do this. Perhaps one of the simplest is to compute the angle associated with each vector, and find the difference.

We can compute that angle as ...

  vector angle = arctan((coefficient of j)/(coefficient of i))

where the arctangent is computed in the appropriate quadrant according to the signs of i and j.

  ∠u = arctan(-8/√5) ≈ -74.38°

  ∠v = arctan(1/√5) ≈ 24.09°

The angle between these vectors is then ...

  24.09° -(-74.38°) = 98.47° ≈ 98.5°

3 0
4 years ago
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