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balandron [24]
3 years ago
11

Find the missing value for X

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0
If we assume that BC is bisecting AD, and that AE is half of AD, we can set up the equation:

2(19)=5x-7

Then we can solve directly for x:

38=5x-7
45=5x
x=9

So we have then calculated x which is equal to 9.
You might be interested in
F(x)=-2(x-3)(x+5) convert quadratic functions to standard form​
jasenka [17]

Answer:

The answer is: f(x) = -2x^2 - 4x + 30

Step-by-step explanation:

Given:

f(x)=-2(x-3)(x+5)

Solve (x-3)(x+5) first, then multiply by -2:

f(x) = -2[(x - 3)(x + 5)]

f(x) = -2[x^2 -3x + 5x - 15]

f(x) = -2[x^2 + 2x - 15]

f(x) = -2x^2 - 4x + 30

Hope this Helps!! Have an Awesome Day!! (-:

4 0
3 years ago
Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=
Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = x^2 + y^2 +z^2 = 4^2

z^2 = 16 -x^2 -y^2

z = \sqrt{16-x^2-y^2}

The partial derivatives of Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}

Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}

Similarly;

Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}

∴

dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA

=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA

=\sqrt{ \dfrac{16}{16-x^2-y^2}  }\ \ .dA

=\dfrac{4}{\sqrt{ 16-x^2-y^2}  }\ \ .dA

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to \sqrt{12}

dA = rdrdθ

∴

The surface area S = \int \limits _R \int \ dS

=  \int \limits _R\int  \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA

= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \  \ rdrd \theta

= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr

= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}

= 8\pi ( - \sqrt{4} + \sqrt{16})

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0
3 years ago
Please help, answers only!!
nikdorinn [45]

The slope of the line in the table given is 11

<h3>Slope of a Line</h3>

In Mathematics, a slope of a line is the change in y coordinate with respect to the change in x coordinate.

The net change in y-coordinate is represented by Δy and the net change in x-coordinate is represented by Δx.

Hence, the change in y-coordinate with respect to the change in x-coordinate is given by

m = y₂ - y₁ / x₂ - x₁

Taking two points from the table

m = 1172 - 864 / 72 - 44

m = 11

The slope of the line is 11

Learn more on slope of a line here;

brainly.com/question/16949303

#SPJ1

8 0
1 year ago
If there are 50 floats in a parade how many ways can a first and second place trophy be awarded
gtnhenbr [62]
I think that the answer is 10,000 ways but i would ask a math teacher.
8 0
3 years ago
Find the value of each variable 4y 3x 8 12​
Scilla [17]

Answer:

4x812y3

Step-by-step explanation:

5 0
3 years ago
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