Check the forward differences of the sequence.
If
, then let
be the sequence of first-order differences of
. That is, for n ≥ 1,

so that
.
Let
be the sequence of differences of
,

and we see that this is a constant sequence,
. In other words,
is an arithmetic sequence with common difference between terms of 2. That is,

and we can solve for
in terms of
:



and so on down to

We solve for
in the same way.

Then



and so on down to


Take the 133 players and divide by 4.
(133 / 4) = 33.25
33 cars can carry (33 x 4) = 132 players.
But that leaves one player out in the cold with no ride.
You need one more car ... 34 cars all together.
Answer:
g(-2)= -19
g(0)= -5
g(3)= -14
Step-by-step explanation:
Answer:
-10
-I-8I = -8
-(-2) = 4
I-11I = 11
5² = 25
Answer: -10, -8, 4, 11, 25