Answer: 
Step-by-step explanation:
The resultant can be calculated using triangular law of vector addition as :
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
Answer:
A
Step-by-step explanation:
Given
y = 2x² - 3x + 1
To find the zeros let y = 0, that is
2x² - 3x + 1 = 0
Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × 1 = 2 and sum = - 3
The factors are - 2 and - 1
Use these factors to split the x- term
2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )
2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(2x - 1) = 0
Equate each factor to zero and solve for x
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = 
x - 1 = 0 ⇒ x = 1
(6,58) (9,82)
You can plug those into the equation,
but point slope form wouldn’t be appropriate for the information given but that’s what the questions asking sooo
Here’s the equation
y − y1 = m(x − x1)
The equation is useful when we know:
one point on the line: (x1,y1)
and the slope of the line: m
The answer is :
0.18181818
But you can also write it like this
