Graph the image of rectangle EFGH after a reflection over the line x=

At Southside Middle School, 30% of the students play an instrument. There are 310 students. How many students play an instrument

rodikova [14]

93 students play an instrument because you would take 310 (the total amount of students) and multiply it by 0.3 (the thirty percent) and get 93

5 0

3 years ago

Group B 8x4=82

Semmy [17]

Answer:

poop

Step-by-step explanation:

7 0

3 years ago

What is the final step of bisecting a line segment

elena55 [62]

Start with a line segment PQ.1Place the compasses on one end of the line segment.2Set the compasses' width to a approximately two thirds the line length. The actual width does not matter.3Without changing the compasses' width, draw an arc above and below the line.4Again without changing the compasses' width, place the compasses' point on the the other end of the line. Draw an arc above and below the line so that the arcs cross the first two.5Using a straightedge, draw a line between the points where the arcs intersect.6Done. This line is perpendicular to the first line and bisects it (cuts it at the exact midpoint of the line).

4 0

4 years ago

A parallelogram-shaped field in a park needs sod. The parallelogram has a base of 22.5 meters and a height of 18 meters. The sod

BigorU [14]

Answer:

22.5 meters plus the amount of sold would equal 2.29

Step-by-step explanation:

6 0

3 years ago

A sample of 35 observations is selected from a normal population. The sample mean is 53, and the population standard deviation i

krok68 [10]

Answer:

Null hypothesis: $\mu = 54$

Alternative hypothesis: $\mu \neq 54$

Two tailed test

So we reject the null hypothesis is $z< -2.58$ or if $z>2.58$

Our calculated value is not on the rejection zone so then we don't have enough evidence to reject the null hypothesis at 0.01 of significance for this case.

Step-by-step explanation:

Data given and notation

$\bar X=53$ represent the sample mean

$\sigma=5$ represent the population standard deviation

$n=35$ sample size

represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 54 or no, the system of hypothesis would be:

Null hypothesis: $\mu = 54$

Alternative hypothesis: $\mu \neq 54$

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{53-54}{\frac{5}{\sqrt{35}}}=-1.183$

Decision rule

Since we are conducting a bilateral test we need to find a value on the normal standarrd distribution that accumulates 0.005 of the area on each tail. And we can use the following excel code: "=NORM.INV(0.005;0;1)"

So we reject the null hypothesis is $z< -2.58$ or if $z>2.58$

Our calculated value is not on the rejection zone so then we don't have enough evidence to reject the null hypothesis at 0.01 of significance for this case.

3 0

3 years ago

Graph the image of rectangle EFGH after a reflection over the line x= –1