Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
<span>f(x) = -6x +6
to find inverse
x = -6y + 6
6y = 6 - x
y = 1 - x/6
Answer
</span>f^–1(x)= 1 - x/6
Answer:
3600 N forward
Step-by-step explanation:
Use Newton's second law.
F = ma
F = 1200 kg × 3.0 m/s²
F = 3600 N
Answer:
Domain: 3, 6, 8, 9, 7
Step-by-step explanation:
Domain: 3, 6, 8, 9, 7
(Domain, Range)
The domain of a function or relation is the set of all possible independent values the relation can take.
Hope this helps :)