Answer:
The rate of reaction of a zero-order reaction is 0.0020 mol/L.
Explanation:
The rate expression of the zero order kinetic are :
[A]= initial concentration of reactant
k = rate constant
R = rate of reaction
We have :
Rate constant of the reaction , k = 0.0020 mol/L s
R = 0.0020 mol/L s
The rate of reaction of a zero-order reaction is 0.0020 mol/L.
Answer:
Ligand
Explanation:
[Ni(H2O)n]2 is a complex, Ni is a central atom, H2O is ligand.
Answer:
pH = 10
Explanation:
KOH is a strong base; thus it will completely dissociate:
KOH -> K⁺ + OH⁻
Since it completely dissociates, the concentration of both K⁺ and OH⁻ will be the concentration of KOH given (1.0 x 10^-4 M).
We can then find pOH by taking the negative log of the OH⁻, or hydroxide, concentration:
pOH = -log[OH⁻] = -log[1.0 x 10^-4 M] = 4
At 25 degrees Celsius, pH + pOH = 14. If we solve for pH and then plug in our pOH, we get:
pH = 14 - pOH = 14 - 4 = 10
The pH of a 1.0 x 10^-4 M solution of KOH is thus 10.
Names of Ionic Compounds<span>. </span>Name<span>. </span>CHEMISTRY<span>: A Study of Matter. © 2004, GPB. 6.16a. KEY. </span>Write<span> the </span>name<span> of </span>each ionic compound below. 1. MgS<span>. </span>2. FeO ... magnesium sulfide iron (II<span>) </span>oxide<span>barium sulfite </span>aluminum<span> hydroxide.</span>
Answer:
The correct answer is: It loses electrons.
Explanation:
In the reactions of oxide reduction (redox), one substance gives up electrons and the other accepts them. Involved: reducing agent (yields electrons, increases its oxidation number: oxidizes) and an oxidizing agent (accepts electrons, decreases its oxidation number: reduces).