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3 years ago

How do you determine bonding capacity of an atom?

Chemistry

2 answers:

Maurinko [17]3 years ago

4 0

Bonding capacity is based on the oxidation number .

STALIN [3.7K]3 years ago

3 0

One of the things you look at is how many electrons does the atom has in its outer shell or how many valance electrons the atom has? if the outer shell is full than atoms are more stable and will not usually bond with other atoms.<span>
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Need help I don't remember what to do?

Lina20 [59]

I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
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3 years ago

Several teeth were found in an area of flat land covered with trees and plants. The teeth were examined by a paleontologist, and

djverab [1.8K]

B because that makes the most sense

3 0

3 years ago

Read 2 more answers

If a star is shown ti be 33.11 trillion killometers away , how many light year would that be

adoni [48]

Use proportions.

1 lightyear = <span>9.4605284 trillion kilometers
</span><span>x light years </span>≈<span> 33.31 </span>trillion kilometers
<span>
33.31/9.46 = x/1
3.50 </span>≈ x<span>

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8 0

3 years ago

What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane

Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂ ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3 moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0

3 years ago

What happened after the gas syringe was inserted into the flask with the methane gas?

ad-work [718]

When a syringe is inserted into the flask containing methane gas the plunger of the syringe is raise up. This led to filling of the syringe with the gas.This relate to Charles law which explain how gas expand with increase in temperature.

7 0

3 years ago