T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15
Multiply the above equation by 1.03 giving
1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16
Now subtract the first equation from the second to give
0.03T = 40000(1.03)^16 - 40000
0.03T = 40000(1.03^16 - 1)
0.03T = 24188.26
T = 24188.26 / 0.03 = $806275.25
Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
Answer: width = 21, length = 47
<u>Step-by-step explanation:</u>
Length (L) = 2w + 5
width (w) = w
Perimeter (P) = 136
P = 2L + 2w
136 = 2(2w + 5) + 2w <em>substituted the given values above</em>
136 = 4w + 10 + 2w <em>distributed 2 on the right side</em>
136 = 6w + 10 <em>added like terms (4w and 2w)</em>
126 = 6w <em>subtracted 10 from both sides</em>
21 = w <em>divided both sides by 6</em>
Length (L) = 2w + 5
= 2(21) + 5
= 42 + 5
= 47
Answer: the square root of 3
Step-by-step explanation:
3. i=129; j=112
4.k=90;l=116;m=64;n=86
5.o=13;p=78;q=91
6.a=120;b=60;c=140
Can't see #7
You did 8 I believe
9.v=39;w=59;x=121
10.y=59;z=93
11.a=42;b=48;c=132
12.a=60;b=50;c=80;d=100
