Joe is riding in a bike race that goes through a valley and a nearby mountain range.

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

5 0

Answer:

a. 224

b. 78

Step-by-step explanation:

a. add 400 to -176

b. subtract 98 from 176

You might be interested in

Write a expression that uses partial products to multiply 8 x 64

krok68 [10]

8 x 64
=64 x 2 x 4
=128 x 2 x 2
=256 x 2
=512

3 0

3 years ago

(K3+2k2-82k-28)/(k+10)

Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

-10 | 1 + 2 - 82 - 28
---------------------------

Now firstly, drop the 1:

-10 | 1 + 2 - 82 - 28
↓
-------------------------
1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

-10 | 1 + 2 - 82 - 28
↓ - 10
-------------------------
1 - 8

Next, multiply -10 and -8, then combine the product with -82:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80
-------------------------
1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

-10 | 1 + 2 - 82 - 28
↓ -10 + 80 + 20
-------------------------
1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is $k^2-8k-2-\frac{8}{k+10}$ </u>