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3 years ago

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Suppose you first want to eliminate the fraction in 4n=1/2(2n-12). What would your first step be? Is -2 still the solution when

you start by eliminating the fraction first? Explain

1 answer:

Lisa [10]3 years ago

7 0

Answer:

Step-by-step explanation:

Recognize that the (1/2) in 4n=1/2(2n-12) is a coefficient, the coefficient of the (2n - 12) term.

Thus, multiply both sides of this equation 4n=1/2(2n-12) by 2, to obtain:

8n = 2n - 12

Combining like terms, we get 6n = -12, so that n = -2.

Multiplying both sides of the equation by a constant does not in any way affect your ability to find a solution and does not change the solution.

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Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year)

jenyasd209 [6]

Answer:

$110\ \text{km/myr} =11\ \text{cm/yr}$

Step-by-step explanation:

To find : Convert 110 km/myr (kilometers per million years) to cm/yr (centimeters per year) ?

Solution :

Using metric conversions,

1 kilometer = 1000 meter

1 meter = 100 centimeter

So, 1 kilometer = 100,000 centimeter

and 1 million year = 1,000,000 year

$1\ \text{km/myr} =\frac{100000}{1000000}\ \text{cm/yr}$

$1\ \text{km/myr} =0.1\ \text{cm/yr}$

So, $110\ \text{km/myr} =110\times 0.1\ \text{cm/yr}$

$110\ \text{km/myr} =11\ \text{cm/yr}$

Therefore, $110\ \text{km/myr} =11\ \text{cm/yr}$

6 0

3 years ago

Read 2 more answers

Need help with this problem. ASAP

Mashutka [201]

Sorry I do not have added

7 0

3 years ago

How many positive integers not exceeding 1000 are not divisible by either 4 or 6?

san4es73 [151]

$\left\lfloor\dfrac{1000}4\right\rfloor=250$

$\left\lfloor\dfrac{1000}6\right\rfloor=166$

$\left\lfloor\dfrac{1000}{\mathrm{lcm}(4,6)}\right\rfloor=\left\lfloor\dfrac{1000}{12}\right\rfloor=83$

$250+166-83=333$

7 0

3 years ago

Dave has 8000 to invest for 15 years. He finds a bank that offers an interest rate of 3.1% compounded monthly. How much money wi

Lynna [10]

Answer: he will have $12720 after 15 years

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $8000

r = 3.1% = 3.1/100 = 0.031

n = 12 because it was compounded 12 times in a year.

t = 15 years

Therefore,

A = 8000(1 + 0.031/12)^12 × 15

A = 8000(1 + 0.00258)^180

A = 8000(1.00258)^180

A = $12720

4 0

3 years ago

Convert,the complex number into polar form: 4+4i

kow [346]

Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656

$cos\theta = \frac{a}{r}$
$cos\theta = \frac{4}{4\sqrt{2}}$
$cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$cos\theta = \frac{4\sqrt{2}}{4(2)}$
$cos\theta = \frac{4\sqrt{2}}{8}$
$cos\theta = \frac{\sqrt{2}}{2}$
$2(cos\theta) = 2(\frac{\sqrt{2}}{2})$
$2cos\theta = \sqrt{2}$
$2cos\theta = 1.414$

$sin\theta = \frac{b}{r}$
$sin\theta = \frac{4}{4\sqrt{2}}$
$sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}$
$sin\theta = \frac{4\sqrt{2}}{4(2)}$
$sin\theta = \frac{4\sqrt{2}}{8}$
$sin\theta = \frac{\sqrt{2}}{2}$
$2(sin\theta) = 2(\frac{\sqrt{2}}{2})$
$2sin\theta = \sqrt{2}$
$2sin\theta = 1.414$

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

$\theta = tan^{-1}\frac{b}{a}$
$\theta = tan^{-1}\frac{4}{4}$
$\theta = tan^{-1}(1)$
$\theta = 45$

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).

5 0

3 years ago