Answer:
1:
<A=½(arcJL)=½(70+120)=35+60=95°
[inscribed angle is half of central angle]
2:
<W=½arcVX=½(130)=65°
[inscribed angle is half of central angle]
3.
<E=½(arcDC)=½(90)=45°
[inscribed angle is half of central angle]
4.
<R=½(arcXZ)=½(110+62)=86°
[inscribed angle is half of central angle]
5.
<B=½(arc DC)=½×104°=52°
[inscribed angle is half of central angle]
6.
<K=90°
[inscribed angle in a diameter is complementary]
<K+<J+<L=180°(sum of interior angle of a triangle]
<L=180°-90°-53°=37°
again
arc JK=2×<L=2×37=74°
Hi there!
13y² + 10y - 3 = 5y²
Begin by moving all terms to one side:
13y² + 10y - 3 - 5y² = 0
Combine like terms:
8y² + 10y - 3 = 0
Factor using the guess-and-check method.
(4y - 1)(2y + 3) = 0
Set each factor equal to 0 to find the solutions:
4y - 1 = 0
4y = 1
y = 1/4
2y + 3 = 0
2y = -3
y = -3/2
Answer:
What do you mean by a "Good estimate"? There's no picture or questions.
Step-by-step explanation:
Answer:
false, false
Step-by-step explanation:
C' is (5, 4)
A' is (5, -4)
Each side of the triangle is larger in the image, and the area is larger.
Answer: false, false
