This problem can be solved through simple arithmetic
progression
Let
a1 = the first term of the sequence
a(n) = the nth term of the sequence
n = number of terms
d = common difference
Sn = sum of all terms
given
a1 = 12
a2 = 16
n = 10
d = 16 -12 = 4
@n = 10
a(n) = a1 + (n-1)d
a(10) = 12 + (9)4
a(10) = 48 seats
Sn = (n/2) * (a1 + a(10))
Sn = 5* (12 + 48)
Sn = 300 seats
Therefore the total number of seats is 300.
Answer:
40z + 5
Step-by-step explanation:
I'm assuming you need to factor 32z + 4 + 8z + 3 - 4 + 2
- 32z + 8z ( since they both have the same variable ) = 40z
- 4 + 3 - 4 + 2 ( since they have to variables ) = 5
Hope this helped
I assume you mean: Order the following from least to greatest:
17/9, 15 divided by 6, 30, and 3^3
17/9 = 1 8/9
15/6 = 2 1/2
3^3 = 9
So it would be: 17/9, 15 divided by 6, 3^3, and 30
Make necessary adjustments if it was actually 6/30; the wording was confusing.
Answer:
is there a question or picture?