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tiny-mole [99]
3 years ago
14

Which equation is in slope intercept form and represents a line with the slope three through the point (9,-4)

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

y = 3x - 31

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 3, thus

y = 3x + c ← is the partial equation

To find c substitute (9, - 4) into the partial equation

- 4 = 27 + c ⇒ c = - 4 - 27 = - 31

y = 3x - 31 ← equation in slope- intercept form

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How do you differentiate y = 3x3 - 2x-4
riadik2000 [5.3K]

Answer:

y' = 9x^2 + 8x^-5

Step-by-step explanation:

General Principle

y' = ax^b

y' = a*b * x^(b-1)

Solution

3x^3 = 3*3x^(3-1)

3x^3 = 9x^2

-2x^-4  = -2*-4 x ^(-4 - 1)

-2x^-4 = 8 x ^-5

Answer

y' = 9x^2 + 8x^-5

7 0
3 years ago
Find the equation of the line that passes through point A (1,7) and B (-3, -1)
amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

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