Answer:
162.5
Step-by-step explanation:
Answer:
(3;0)
(0;15)
y=-5x+15
Step-by-step explanation:
x-intercept
-5x–0=-15
-5x=-15
-5x/-5=-15/-5
x=3 》》(3;0)
y-intercept
-5(0)-y=-15
y=15 》》 (0;15)
slope intercept form
y=mx+b
m=Y2–Y1/X2–X1
=15–0/0–3
=15/-3
=-5
evalute (0;15) & m=-5 in y=mx+b
15=-5(0)+b
15=b
so
y=-5x+15
Answer:
The answer is "
f and g are arbitrary".
Step-by-step explanation:
The matrix of the device is increased
![\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%26f%5C%5C%20c%26d%26g%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Reduce the echelon row matrix
![\left[\begin{array}{ccc}1&3&f\\ c&d&g\\ \end{array}\right] \\\\R_1 \leftrightarrow R_2 \\\\\frac{R_2 -1}{C R_1 \to R_2} \sim \left[\begin{array}{ccc} c&d&g\\ 0 & \frac{3c-d}{c}& \frac{cf-g}{c}\\ \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%26f%5C%5C%20c%26d%26g%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CR_1%20%5Cleftrightarrow%20%20R_2%20%5C%5C%5C%5C%5Cfrac%7BR_2%20-1%7D%7BC%20R_1%20%5Cto%20R_2%7D%20%20%20%5Csim%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20c%26d%26g%5C%5C%200%20%26%20%5Cfrac%7B3c-d%7D%7Bc%7D%26%20%5Cfrac%7Bcf-g%7D%7Bc%7D%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Therefore, if 3c
0 is d 3c, the device is valid. Therefore d are arbitrary 3c, g and f.
It’s definitely B I believe
Answer:
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