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2 years ago

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pleaseeee help please for f(x) = x2 and g(x) = (x − 3)2, in which direction and by how many units should f(x) be shifted to obta

in g(x)? a) left 3 units b) right 3 units c) up 3 units d) down 3 units

2 answers:

rusak2 [61]2 years ago

6 0

Answer:

Right 3 units.

wariber [46]2 years ago

4 0

F(x) should be shifted right 3 units.

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Help I need help right now pls someone and thanks

wariber [46]

C because i took the test

3 0

2 years ago

Read 2 more answers

3x-2y=-1. <br> Y=-x+3. <br> Is (1,2) a solution do the system?

andrew-mc [135]

Answer:

Yes

Step-by-step explanation:

To figure out if (1,2) is a solution to the system, we can plug the values in and see if it is true.

3x-2y=-1

3(1)-2(2)=-1

3-4=-1

-1=-1

It is true for this equation. Now let's check the next one.

y=-x+3

2=-(1)+3

2=2

Since both equations are true when we plug the values in, (1,2) is a solution to the system.

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2 years ago

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26 out of the 65 magazines at the bookstore are women's magazines. What percentage of the magazines at the bookstore are women's

egoroff_w [7]

The fraction $\frac{26}{64}$ represents the number of women's magazines out of all the other magazines at the book store.

To find what percent of the magazines are women's magazines, we can turn $\frac{26}{64}$ into a percent.

To write a fraction as a percent in lowest terms, first remember that a percent is a ratio of a number to 100 so to write 26/64 as a percent, we need to find a fraction equivalent to 26/64 with 100 in the denominator. We can do this by setting up a proportion.

40% is the answer

IMAGE PROVIDED.

7 0

2 years ago

What’s the answer I don’t understand it or know it.

fredd [130]

Answer:

I tried solving it and didn't get same exact numbers but I got 8.67 million people so it might be answer choice B.

7 0

2 years ago

Which of the equations below could be the equation of this parabola?

nirvana33 [79]

Answer:

$y=-4x^2$ is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

$y=-4x^2$

$\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

$\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}$

$\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)$

As

$\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)$

$\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}$

$y=-4x^2$

$\mathrm{The\:parabola\:params\:are:}$

$a=-4,\:m=0,\:n=0$

$x_v=\frac{m+n}{2}$

$x_v=\frac{0+0}{2}$

$x_v=0$

$\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}$

$y_v=-4\cdot \:0^2$

$y_v=0$

Therefore, the parabola vertex is

$\left(0,\:0\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}$

$a=-4$

$\mathrm{Maximum}\space\left(0,\:0\right)$

so,

$\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)$

Therefore, $y=-4x^2$ is the equation of this parabola. The graph is also attached.

7 0

3 years ago