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3 years ago

15

pleaseeee help please for f(x) = x2 and g(x) = (x − 3)2, in which direction and by how many units should f(x) be shifted to obta

in g(x)? a) left 3 units b) right 3 units c) up 3 units d) down 3 units

2 answers:

rusak2 [61]3 years ago

6 0

Answer:

Right 3 units.

wariber [46]3 years ago

4 0

F(x) should be shifted right 3 units.

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Find the area of a regular pentagon with the apothem of 24.3 cm and a side length of 35.3

steposvetlana [31]

Answer: $A=2144\ cm^2$

Step-by-step explanation:

For this exercise you need to use the following formula for calculate the area of regular polygon:

$A=\frac{s^2n}{4tan(\frac{180}{n})}$

Where is "s" the length of any side, "n" is the number of sides.

Int this case you know that it is regular pentagon, which means that it has five sides. Then you can identify that the values of "n" and "s":

$s=35.3cm\\n=5$

Therefore, substituitng values into the formula, you get that the area f the pentagon is:

$A=\frac{(35.3cm)^2(5)}{4tan(\frac{180}{5})}\\\\A=2144\ cm^2$

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3 years ago

List the fractions in descending order of 2/5 8/9 4/5 1/3 3/10

snow_lady [41]

Answer:

8/9, 4/5, 2/5, 1/3, 3/10

Step-by-step explanation:

2/5 = 0.4 8/9 = 0.888 4/5 = 0.8 1/3 = 0.333 3/10 = 0.3

8 0

3 years ago

Given f(x)=cos c and g(x)=cot x, what are the domain and range of f(g(x))?

ololo11 [35]

Answer:

Alternative C is the correct answer

Step-by-step explanation:

The first step is to determine the composite function;

$f[g(x)]$

$f[g(x)]=cos[cot(x)]$

We then employ a graphing utility to determine the range and the domain of the new function.

The range is the set of y-values for which the function is defined. In this case it is;

$[-1,1]$

On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.

8 0

3 years ago

Can someone please explain to me how to solve this?

lyudmila [28]

I hope this helps you

x= -2

h (-2)= 3. (-2)+1

h (-2)=-6+1

h (-2)= -5

4 0

3 years ago

The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.

slamgirl [31]

Answer:

$b=-6\\c=7$

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

$y=a(x-x_1)(x-x_2)$

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

$a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}$

substitute

$y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

Applying the distributive property convert to expanded form

$y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})$

$y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)$

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therefore

$b=-6\\c=7$

7 0

3 years ago