We want to find the total number of integers that are larger than 40 and smaller than 99 that also are multiples of 3.
The answer is 18.
We can solve this just by counting.
The first multiple of 3 larger than 40 is:
3*14 = 42
Now we know that 99 is also a multiple of 3 and that the multiples of 3 are separated by a distance of 3 units, then the total number of multiples of 3 between 42 and 99 is given by:
(99 - 42)/3 = 19
But we need to remove 1, because we used 99 and we have the restriction that our numbers must be "smaller" than 99.
Then we have a total of 18 multiples of 3 between 40 and 99.
If you want to learn more, you can read:
brainly.com/question/19239363
Answer: 208.
Step-by-step explanation:
The formula to find the minimum sample size is given by :-
(1)
, where z* = critical z-value (two tailed).
= Standard deviation ( from prior study ) and E = Margin of error.
As per given , we have
Margin of error : E= 0.29
Confidence level = 85%
Significance level =
Using z-table , the critical value (two -tailed)=
As per previous study , Variance =
Now, the required minimum sample size = 
[Substitute the values in formula (1)]
[ Round to the next integer]
Hence, the minimum number of third graders that must be included in a sample = 208.
Answer:
I believe it's <u>true</u>.
This is the solution to your equation.
