Suppose LCM(a,b) = 20160, a=60. Find the smallest possible value of b.
2 answers:
Answer:
63
Step-by-step explanation:
1260=22*32*5*7
60=22*3*5
Therefore we need the smallest number divisible by seven and nine, which is 7*9=63.
Answer:
see below
Step-by-step explanation:
given:
LCM(a,b) = 20160, a=60
find:
smallest possible value of b
solution;
60, b = 20,160
b = 20,160 / 60
b = 336
60 x 336 = 20,160
= 2⁶ x 3² x 5 x 7
= (2² x 3 x 5) x (2⁴ x 3 x 7)
= (60) x (336)
LCM(60,336) = 1680
consider the 2² x 3 to get the prime number:
= 336 x 12
= 4032
therefore,
LCM(60,4032) = 20160
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Answer:
52
Step-by-step explanation:
miles per hour so 208, which is miles and 4 which is hours so 208/4 which is 52
The firs t res is x=4
the second is D
10/002728182.2777272829 error
A. You can factor it to those terms
It would be 40n + 7=x!!!
Hope this helps have a good day!!!
