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vodomira [7]
3 years ago
5

If XY​,=30 XZ=24​, and JQ​=8, find the radius of the circumscribed circle of XYZ Please Help Brainliest if correct! Thanks!

Mathematics
1 answer:
uysha [10]3 years ago
6 0
<h3><u>Given</u>;</h3>

XY = 30, XZ = 24, JQ = 8

From the given diagram we can see that;

XJ = JY

So,

XJ = JY = XY/2

XJ = JY = 30/2 = 15

Here, Point Q is the centroid of the ∆XYZ, which means that <u>XQ = QZ = QY</u> will be the radius of the circumscribed circle.

Since,

We know JQ and XJ, let us consider triangle XJQ.

By Using Pythagoras Theorem;

(XQ)² = (XJ)² + (JQ)²

(XQ)² = (15)² + (8)²

(XQ)² = 225 + 64

(XQ)² = 289 +

XQ = √289

XQ = 17

Thus, The radius of the circumscribed circle of ∆XYZ is 17

 

<u>-TheUnknownScientist</u><u> 72</u>

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The height and diameter of a cone-shaped storage tank are 9 feet (height) and 14 feet
lana [24]

Answer: 461.60 is the volume of liquid the tank can hold.

Step-by-step explanation:

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Solve the following pair of equations by elimination method: x+y=4, 2x+y=3​
allsm [11]

Answer:

x = 1

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Step-by-step explanation:

x + y = 4 __ (1)

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equation (1) x 2, (2) x 1

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I HOPE MY ANSWER IS CORRECT IF NOT I APOLOGIZE.

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