Question

If XY​,=30 XZ=24​, and JQ​=8, find the radius of the circumscribed circle of XYZ Please Help Brainliest if correct! Thanks!

Answer 1

Given;

XY = 30, XZ = 24, JQ = 8

From the given diagram we can see that;

XJ = JY

So,

XJ = JY = XY/2

XJ = JY = 30/2 = 15

Here, Point Q is the centroid of the ∆XYZ, which means that XQ = QZ = QY will be the radius of the circumscribed circle.

Since,

We know JQ and XJ, let us consider triangle XJQ.

By Using Pythagoras Theorem;

(XQ)² = (XJ)² + (JQ)²

(XQ)² = (15)² + (8)²

(XQ)² = 225 + 64

(XQ)² = 289 +

XQ = √289

XQ = 17

Thus, The radius of the circumscribed circle of ∆XYZ is 17

 

-TheUnknownScientist 72