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Sliva [168]
3 years ago
8

It takes Ernesto 27 minutes to walk from his house to the

Mathematics
1 answer:
anygoal [31]3 years ago
6 0
9:12 is when he left
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Which represents the solution(s) of the graphed system of equations, y = x2 + 2x – 3 and y = x – 1?
Sonja [21]

Answer:

Second option: (-2,-3) and (1,0)

Step-by-step explanation:

Given the system of equations \left \{ {{y = x^2 + 2x-3} \atop {y = x - 1}} \right., you can rewrite them in this form:

x^2 + 2x-3= x - 1

Simplify:

x^2 + 2x-3-x+1=0\\\\x^2+x-2=0

Factor the quadratic equation. Choose two number whose sum be 1 and whose product be -2. These are: 2 and -1, then:

(x+2)(x-1)=0\\\\x_1=-2\\\\x_2=1

Substitute each value of "x"  into any of the original equation to find the values of "y":

y_1= (-2) - 1=-3\\\\y_2=(1)-1=0

Then, the solutions are:

(-2,-3) and (1,0)

7 0
3 years ago
Read 2 more answers
Colin took out a loan with a principal of $32,800. After five years, the interest and the principal totaled $48,872. If Colin ma
yulyashka [42]
C hope that can help you
8 0
3 years ago
What is the first term in the sequence for which d = -2 and a7 = 3?
AnnZ [28]

Answer:

Final answer is c. 15

Step-by-step explanation:

We need to find about what is the first term in the sequence for which d = -2 and a7 = 3

We will use nth term formula of arithmetic sequence.

a_n=a+\left(n-1\right)d

we have been given a7 that means 7th term is 3

so plug n=7, d=-2 and a_n=3 into above formula

3=a+\left(7-1\right)(-2)

3=a+6(-2)

3=a-12

15=a

Hence final answer is c. 15

7 0
3 years ago
Read 2 more answers
Solve by completing the square: 5x2 + 20x + 32 = 0
igor_vitrenko [27]
Your answer is no solution (because a negative square root doesn't exist)
first, you divide all sides by five and then take b, half it then square it

5 0
3 years ago
translate the word phrase into a math expression.  nine more than five times a number                                          
EastWind [94]
It is definitely a. 9>5n
Because it say 9 is more than five times a number and if you have any questions just comment an I'll try to help! :) Hope I helped!
8 0
3 years ago
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