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3 years ago

I need help solving it

Mathematics

1 answer:

Advocard [28]3 years ago

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4 fraction 3/10 hope it helped you

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Find a,b,c and d?..........

cupoosta [38]

9514 1404 393

Answer:

a = 6, b = 12, c = 6, d = 6√3

Step-by-step explanation:

The two triangles are the "special" triangles.

The 45-45-90 triangle has side lengths in the ratios 1 : 1 : √2.

The 30-60-90 triangle has side lengths in the ratios 1 : √3 : 2.

Then ...

c : a : 6√2 = 1 : 1 : √2 ⇒ c = a = 6

and ...

a : d : b = 1 : √3 : 2 ⇒ d = 6√3 and b = 12 . . . (since a=6)

The lengths are ...

a = 6, b = 12, c = 6, d = 6√3

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2 years ago

USA test prep please answer

sergij07 [2.7K]

Answer:

Step-by-step explanation:

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3 years ago

The Jayden family eats at a restaurant that is having a 15% discount promotion. Their meal costs $78.25 before the discount, and

soldi70 [24.7K]

Answer:

$82.16

Step-by-step explanation:

78.25 * .20 = 15.65 as a tip,

78.25 *.15 = 11.74 as the discount, subtract from initial value:

78.25 - 11.74 = 66.51

then add the tip: 15.65 + 66.51 = $82.16

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2 years ago

A store increases the price of a sweater from $20 to $22. What is the percent of increase? Select from the drop-down menu to cor

o-na [289]

Price increase is $ 22-20 =$2 so the percent increase is 2/20 x 100= 10%

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3 years ago

Read 2 more answers

Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de

Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

$H_0: \mu=7\\\\H_a:\mu> 7$

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25$

The degrees of freedom for this sample size are:

$df=n-1=49-1=48$

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t>5.25)=0.000002$

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0

3 years ago