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Katena32 [7]
3 years ago
8

Which numbers below are solutions to the inequality 4y+3≤−7?

Mathematics
1 answer:
MariettaO [177]3 years ago
4 0

Answer:

answer is in picture

Step-by-step explanation:

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A.(-2,3)<br> B.(1,4)<br> C.(3,0)<br> D.(-5,-4)
lina2011 [118]

Answer:

D. (-5, -4)

Step-by-step explanation:

3 0
3 years ago
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Find an equation for the line with slope m = -6/7<br> and which goes through the point (14, 4).
sammy [17]

Answer:

y = -6/7x + 16

Step-by-step explanation:

Use the slope intercept equation, y = mx + b

Plug in the slope and given point, then solve for b:

y = mx + b

4 = -6/7(14) + b

4 = -12 + b

16 = b

Plug in the slope and b into the equation:

y = mx + b

y = -6/7x + 16

So, the equation is y = -6/7x + 16

7 0
3 years ago
BRAINLIEST FOR FIRST PERSON WHO SOLVES QUESTION
Sladkaya [172]

Answer:

Step-by-step explanation:

a) V= A*h            V=40*8=320

b) V=800 and h=20

A=V/h=800/20=40

7 0
3 years ago
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Simplify: (6x-5) - (3x-2)
Kaylis [27]

Answer:

3x-3

Step-by-step explanation:

(6x-5) - (3x-2)

remove parenthesees (Not needed

6x-5 - 3x-2

simplify

3x-5-2

3x-3

6 0
3 years ago
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Determine which of the sets of vectors is linearly independent. A: The set where p 1(t) = 1, p 2(t) = t 2, p 3(t) = 1 + 5t B: Th
denis-greek [22]

Answer:

(A)A and C

Step-by-step explanation:

In each case, represent each of the p_i as a column vector where  each row corresponds to the constant term, coefficient of t and t^2 respectively.

A= The set where p_1(t)=1 p_2(t)=t^2 p_3(t)=1+5t

A=\left[\begin{array}{ccc}1&0&1\\0&0&5\\0&1&0\end{array}\right]

|A|=\left|\begin{array}{ccc}1&0&1\\0&0&5\\0&1&0\end{array}\right|=-5

B: The set where p_1(t)=t, p_2(t)=t^2, p_3(t)=2t+5t^2

B=\left[\begin{array}{ccc}0&0&0\\1&0&2\\0&1&5\end{array}\right]\\|B|=0

C: The set where p_1(t)=1, p_2(t)=t^2, p_3(t)=1+5t+t^2

C=\left[\begin{array}{ccc}1&0&1\\0&0&5\\0&1&1\end{array}\right]\\|C|=-5

Since the determinants of A and C are not 0, the set of vectors in A and C are linearly independent.



6 0
3 years ago
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