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MaRussiya [10]
2 years ago
7

Work out a) 4 1/3 x 6 b) 2 3/5 x 3 1/3

Mathematics
2 answers:
scoundrel [369]2 years ago
7 0

Answer:

a) 26

b) 26/3

Step-by-step explanation:

a) 4 and 1/3 = 13/3

13/3 x 6/1 = 13/1 x 2/1

b) 2 and 3/5 = 13/5, 3 and 1/3 = 10/3

13/5 x 10/3 = 13/1 x 2/3

Slav-nsk [51]2 years ago
3 0

Answer:

a) 26

b) 26/3 = 8 2/3

Step-by-step explanation:

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What is true about AngleQRT? Select two options.
stiv31 [10]

The complete question is

"Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T and Q T are congruent. Line segments S R and R Q are congruent. Angles S T R and R T Q are congruent. What is true about AngleQRT?

Select two options. Measure of angleQRT = 90° Measure of angleQRT = Measure of angleSRT AngleQRT Is-congruent-to AngleSTQ Measure of angleQRT = 2*Measure of angleRTQ AngleQRT Is-congruent-to AngleRTQ"

The true about AngleQRT options are A abd B; ∠QRT = 90 and ∠QRT = ∠SRT

<h3>What is the congruent triangle?</h3>

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

Given information;

The triangle QST is isosceles with QT ≅ ST.

The ∠STR and ∠RTQ are congruent.

Now, consider two triangles ∠QTR and ∠STR

In the following triangle

TR  ≅  TR

QTR ≅ STR

QT ≅ ST

Now, according to SAS rule, two congruent triangles have congruent corresponding to their sides,

1. QR ≅ SR

2. QRT ≅ SRT

Since the above two angles are congruent so, they will have the same measure

That will be 90 degree.

Hence, The correct options are; ∠QRT = 90 and ∠QRT = ∠SRT

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1 year ago
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Answer:

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Step-by-step explanation:

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In quadrilateral ABCD, AD ∥ BC. Quadrilateral A B C D is shown. Sides A D and B C are parallel. The length of A D is 3 x + 7 and
oksian1 [2.3K]

Answer:

  31 units

Step-by-step explanation:

When the figure is a parallelogram, opposite sides have the same measure:

  AD = BC

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The length of segment AD must be 31 units for ABCD to be a parallelogram.

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