X+2y-6=z, 3y-2z=74, 4+3x=2y-5z rearrange all to the form ax+by+cz=n
x+2y-z=6, 3y-2z=74, 3x-2y+5z=-4
eliminate x from the 1st and 3rd equations...
-3(x+2y-z=6)+(3x-2y+5z=-4)
-3x+3x-6y-2y+3z+5z=-18-4
-8y+8z=-22 and the 2nd equation was 3y-2z=7, now we can eliminate z
(-8y+8z=-22)+4(3y-2z=7)
-8y+12y+8z-8z=-22+28
4y=6
y=1.5, making 3y-2z=7 become:
3(1.5)-2z=7
4.5-2z=7
-2z=2.5
z=-1.25, making x+2y-z=6 become
x+2(1.5)-(-1.25)=6
x+3+1.25=6
x+4.25=6
x=1.75
So (x,y,z)=(1.75, 1.5, -1.25)
Answer:
you need to show a picture
–x + y = –3 (a)
3x + 2y = 9 (b)
Lt's eliminate y , by multiplying a) by -2
-2(–x + y) = -2(–3) → +2x - 2y = +6 (c). Now add (c) to (b)
+2x - 2y = +6 (c).
3x + 2y = 9 (b)
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5x + 0 = 15 and x = 15/5 and x = 3
To find y, plugin the value of x in any of the equation, sat (a):
–x + y = –3 (a) → -3 + y = -3; y = -3+3 → y = 0
So the solution is (3,0) Answer C
Answer:
120 + 20π
Step-by-step explanation:
Find the image of the question attached.
For the square;
Perimeter of a square = 4L
L is the side length of the square
From the diagram, L = 10
Perimeter of a square = 4(10) = 40
Perimeter of 3 squares = 3(40) = 120
For the semicircles:
Perimeter of a semicircle = 2πr/2 = πr
From the diagram;
L = radius of the semicircle = 10
Perimeter of a semicircle = π(10)
Perimeter of a semicircle = 10π
Perimeter of the two semicircles = 2(10π) = 20π
perimeter of the shape = perimeter of 3squares + 2 semicircles
perimeter of the shape = 120 + 20π
Chris had 8 eggs Lea had 4 eggs
<span>How i got the awnser: 8 - 6 = 2, </span><span>4 - 2 = 2</span>