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ipn [44]
3 years ago
5

Write the standard form of the line that has a slope of -3/4 and y-intercept of -2. Include your work in your final answer. Type

your answer in the box provided or use the upload option to submit your solution.
Mathematics
2 answers:
nevsk [136]3 years ago
8 0

Answer:

The answer is 2y+3x+4 = 0

Step-by-step explanation:

The standard formula for finding equation of a line is expressed as;

y = mx+c where;

m is the slope/gradient

c is the intercept i.e tgw point where the line cuts the y axis

Given slope of -3/4 and y intercept of -2;

m = -3/2, c = -2

Substituting this given values into the formula for equation of a line we have;

y = -3x/2+(-2)

y = -3x/2-2

Multiplying the resulting equation through by 2 gives;

2y = -3x-4

2y+3x+4 = 0

Nataliya [291]3 years ago
7 0

3x + 4y = - 8

The equation of a line in standard form is Ax + By = C

where A is a positive integer and B, C are integers

Express the line in ' slope- intercept form '

y = mx + c → (m is the slope and c is the y-intercept)

here m = - \frac{3}{4} and c = - 2

hence y = - \frac{3}{4} x - 2 → equation in slope- intercept form

multiply all terms by 4

4y = - 3x - 8

add 3x to both sides

3x + 4y = - 8 → in standard form


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A + (b-4) when a-24 and b-7
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Jill has a 25% off coupon for some computer software. If the coupon saved her $35, how much would the software cost without the
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A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

5 0
3 years ago
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