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bulgar [2K]
3 years ago
12

Solve for a side in right triangles.

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer:

BC=15.01

(work is shown in picture)

olga55 [171]3 years ago
6 0

Answer:

6.34

Step by step instructions:

tan(65°) = a/7

7 x tan(65°) = a

a = 6.34

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Find the point that lies on the line described by the equation below.y - 3 = 4(x - 10)
inessss [21]

Answer:

the answer is (3, 10) (4, 14)

Step-by-step explanation:

4 0
3 years ago
X^2-6=2-18x solve by completing the square
AnnyKZ [126]
X^1=-9[89],x^2=-9+[89]
6 0
3 years ago
I need help and i would appreciate it and can you explain (That's if you can explain)
Finger [1]

Answer:

x=-2

y=-3

Step-by-step explanation:

-9x+4y = 6

9x+5y = -33

We will add these together to eliminate x

-9x+4y = 6

9x+5y = -33

----------------

0x +9y =- 27

9y = -27

Divide by 9

9y/9 = -27/9

y =-3

We still need to find x

9x +5y = -33

9x +5(-3) = -33

9x-15 = -33

Add 15 from each side

9x+15-15 =-33+15

9x=-18

Divide by 9

9x/9 = -18/9

x = -2

6 0
4 years ago
Answer now!!! Please!!! (Math)
Serggg [28]

<u>Answer:</u>

The correct answer option is \frac{25}{9}.

<u>Step-by-step explanation:</u>

We are given the following expression and we are to evaluate it when a = 5 and k = -2:

[\frac{3^2a^{-2}}{3a^{-1}} ]^k

Substituting the given values of  a and k to get:

[\frac{3^2(5)^{-2}}{3(5)^{-1}} ]^{-2}

\frac{3^{(2\times -2)}.5^{(1\times-2)}}{3^{(-1\times-2)}.5^{(2\times-2)}}

\frac{3^{-4}.5^{-2}}{3^{-2}.5^{-4}}

3^{-2}.5^2

\frac { 1 } { 3 ^ 2 } . 2

\frac { 1 } { 9 } . 2 5

\frac { 2 5 } { 9 }

4 0
3 years ago
I need help with this question...<br> 2x + 3 ≤ 13
jenyasd209 [6]

Answer: x ≤ 5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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