Answer:
B
Step-by-step explanation:
So base on the statement that you give that states that the first normal curves has a larger mean that the second, must i have a larger standard deviation, to answer that, you must first consider that the standard deviation is not dependent or directly proportional to its mean, the deviation is base on the data of the problem
Centre angle will be 360° as its totally a circle.
Angle between two cars=360/20=18°
![\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%3D%5Cdfrac%7B%5Ctheta%7D%7B360%7D%282%5Cpi%20r%29)
![\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%3D%5Cdfrac%7B18%7D%7B360%7D%282%5Cpi%2825%29%29)
![\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%3D%5Cdfrac%7B1%7D%7B20%7D%2850%5Cpi%29)
![\\ \sf\longmapsto L=2.5\pi ft](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20L%3D2.5%5Cpi%20ft)
Now
Area be A
![\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20A%3D%5Cdfrac%7B1%7D%7B2%7DLr%5E2)
![\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20A%3D%5Cdfrac%7B1%7D%7B2%7D%282.5%5Cpi%29%2825%29%5E2)
![\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20A%3D625%282.5%29%5Cpi%5Cdfrac%7B1%7D%7B2%7D)
![\\ \sf\longmapsto A=1562.5\pi/2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20A%3D1562.5%5Cpi%2F2)
![\\ \sf\longmapsto A=781\pi ft^2=](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20A%3D781%5Cpi%20ft%5E2%3D)
3x^2 + 8x - 4 - (6x^2 - 5x + 3)....distribute thru the parenthesis
3x^2 + 8x - 4 - 6x^2 + 5x - 3 .....combine like terms
-3x^2 + 13x - 7 <==