Th graph of looks exactly like the graph of if we shifted the axes units to the left. This has the visual effect of shifting the graph <em>forward </em> units (imagine filming someone and panning the camera to the left; the person moves <em>right</em> in the camera frame).
So the point at , which used to be is now , which we can find on the <em>first graph</em>.
Y-3=4/11(x-11). Doing a problem like this is mostly memorizing point slope formula, by knowing y-y2=m(x-x1) you can just "plug" in 3 as your y1 and 11 as your x1 then finally 4/11 as your slope being y-3=4/11(x-11)