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ad-work [718]
3 years ago
15

m∠3 is (3x + 4)° and m∠5 is (2x + 11)°. Angles 3 and 5 are . The equation can be used to solve for x. m∠5 = °

Mathematics
2 answers:
ratelena [41]3 years ago
7 0

I just did this question!

Answers:

1) <em>same side interior angles</em>

2) (3x+4)+(2x+11) = 180

3) 77


Sveta_85 [38]3 years ago
5 0

Answer:

Part a) consecutive interior angles

Part b) (3x+4)\°+(2x+11)\°=180\°

Part c) m∠5=77\°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

<u>Part a)</u> Angles 3 and 5 are consecutive interior angles

therefore

m∠3+m∠5=180\°

<u>Part b)</u> we have

m∠3=(3x+4)\°

m∠5=(2x+11)\°

substitute

(3x+4)\°+(2x+11)\°=180\°

<u>Part c)</u> solve for x

(5x+15)\°=180\°

5x=180\°-15\°

x=180\°-15\°=33\°

Find the value of m∠5

m∠5=(2(33)+11)\°

m∠5=77\°

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Step-by-step explanation:

240.70×4=962.8 (for return)

569×4=2240 (hotel cost)

28×4=112 (return airport)

962.8+2240+112=3,314.8

it will cost $3,314.8 for a family of 4.

5 0
2 years ago
What is the length of side ab in equilateral triangle abc if the length of altitude ad to side bc is 12?
I am Lyosha [343]
\lim_{n \to \infty} a_n
6 0
3 years ago
Solve: x³-7x²+36=0.​
Aliun [14]

Answer:

3,6,-2

Step-by-step explanation:

a+2a+b = 7

2a^2b = -36

a*2a + ab + 2ab = 0

or, a(2a+3b) = 0

so, b = -2a/3

Solve those and you find 3,6,-2

3 0
3 years ago
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t
rosijanka [135]

Answer:

Height = 12cm

Radius = 6cm

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

V = 432\pi

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

V = \pi r^2h\\

Substitute 432π for V

432\pi = \pi r^2h

Divide through by π

432 = r^2h

Make h the subject:

h = \frac{432}{r^2}

Surface Area (A) of a cylinder is calculated as thus:

A=2\pi rh+2\pi r^2

Substitute \frac{432}{r^2} for h in A=2\pi rh+2\pi r^2

A=2\pi r(\frac{432}{r^2})+2\pi r^2

A=2\pi (\frac{432}{r})+2\pi r^2

Factorize:

A=2\pi (\frac{432}{r} + r^2)

To minimize, we have to differentiate both sides and set A' = 0

A'=2\pi (-\frac{432}{r^2} + 2r)

Set A' = 0

0=2\pi (-\frac{432}{r^2} + 2r)

Divide through by 2\pi

0= -\frac{432}{r^2} + 2r

\frac{432}{r^2} = 2r

Cross Multiply

2r * r^2 = 432

2r^3 = 432

Divide through by 2

r^3 = 216

Take cube roots of both sides

r = \sqrt[3]{216}

r = 6

Recall that:

h = \frac{432}{r^2}

h = \frac{432}{6^2}

h = \frac{432}{36}

h = 12

Hence, the dimension that requires the least amount of material is when

Height = 12cm

Radius = 6cm

3 0
3 years ago
Which is answer if not know please solve for mw
Vlad1618 [11]
<h3>Answers:</h3><h3>Area of parallelogram = 63</h3><h3>Area of triangle = 34</h3><h3>Area of trapezoid = 84</h3><h3>The trapezoid has the largest area</h3>

==================================================

Work Shown:

area of parallelogram = base*height

area of parallelogram = 9*7

area of parallelogram = 63

----------

area of triangle = (1/2)*base*height

area of triangle = (1/2)*10*6.8

area of triangle = 34

----------

area of trapezoid = height*(base1+base2)/2

area of trapezoid = 6*(13+15)/2

area of trapezoid = 6*(28)/2

area of trapezoid = 168/2

area of trapezoid = 84

5 0
3 years ago
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