Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
No
Step-by-step explanation:
The sample size wasn't big enough. It could only be a trend in that grade.
Answer:
Given sides 12, 16 and 20 can be the sides of right triangle.
Step-by-step explanation:
Sides of right triangle always follow the Pythagoras theorem.
i.e 
For the given Lengths 7, 40 and 41
We need to check if


That means, 
hence 7,40 and 41 can not be the sides of right triangle.
Next,
Given sides 12,16 and 20.
Again follow the similar process used in the above problem.

Therefore given sides 12,16 and 20 can be the sides of right triangle.
Number 2 is 6
i dont know number 3
<span> number 4 is _x-intercept = -12/11 = -1.09091 y-intercept = -12/4 = -3
</span>number 5 is x=12 ,<span>y=<span>−8</span></span><span>y=<span>-<span>8</span></span></span>