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Maurinko [17]
3 years ago
12

Describe how (23)(2-4) can be simplified. (3 and -4 are powers i dont have the knowledge to make the -4 and 3 tiny and stay by t

he upper corner)
1)Multiply the bases and add the exponents. Then find the reciprocal and change the sign of the exponent.

2)Keep the same base and add the exponents. Then multiply by –1.

3)Keep the base and multiply the exponents. Then multiply by –1.

4)Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.
Mathematics
2 answers:
jasenka [17]3 years ago
4 0

Answer:

idk

Step-by-step explanation:

masya89 [10]3 years ago
3 0

Answer:

4)Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent

Step-by-step explanation:

The question can be written as

(2³)(2⁻⁴)

Apply laws of indices, Keep the same base and add the exponents

2^3*2^{-4} \\\\\\2^{3+-4} \\\\\\2^{-1} \\\\

This can be expressed as;

2^{-1} \\\\=\frac{1}{2^1} \\\\=\frac{1}{2} \\\\\\=0.5

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Answer soon please!
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An exponent is also called___.
bija089 [108]

Answer:

An expression that represents repeated multiplication of the same factor is called a power.

Step-by-step explanation:

The number 5 is called the base, and the number 2 is called the exponent. The exponent corresponds to the number of times the base is used as a factor.

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2 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

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What’s the answer to 10=7-m
dsp73

Answer:

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10=7-m

m=7-10=-3

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