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Alexeev081 [22]
3 years ago
9

I’ll give brainliest and a 100 points

Mathematics
2 answers:
Georgia [21]3 years ago
8 0

Answer:

130.5ft²

Step-by-step explanation:

Hello There!

The figure shown is a composite figure ( so we can't find the area of it using one formula )

That being said we want to break the irregular figure into regular figures in which the area can simply be found using a formula

The figure would be broken in to the following shapes

A rectangle with a width of 4 ft and a length of 9 ft

A rectangle with a width of 8 ft and a length of 9 ft

A triangle with a height of 5 ft and a base of 9 ft

Now that we have broken the irregular figure into regular shapes we want to find the area of each individual shape

For the smaller rectangle:

The area of a rectangle can simply be calculated by multiplying the width and length

So A = 9 * 4

9 * 4 = 36

so the area of the smaller rectangle is 36ft²

For the larger rectangle

Once again the area can simply be found by multiplying the width and length

A = 8 * 9

8 * 9 = 72

so the area of the larger rectangle is 72ft²

For the triangle

To find the area of a triangle we want to use this formula

A = \frac{bh}{2}

where b = base and h = height

We have already identified the base and height so all we have to do is plug in the values into the formula

A=\frac{5*9}{2} \\5*9=45\\\frac{45}{2} =22.5

so the area of the triangle is 22.5ft²

Finally we add the areas of each regular figure

22.5 + 72 + 36 = 130.5

so we can conclude that the area of the composite figure is 130.5ft²

ycow [4]3 years ago
6 0

Answer: 130.5ft^2

Step-by-step explanation:

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A club with 12 members is to choose three officers president vice-presidents and secretary-treasurer if each office is to be hel
lesya692 [45]

Answer:

12P3 = 1320

Step-by-step explanation:

How you need select three persons of a group of twelve persons, but in the selection each member of the group has a different position, then you need use a permutation

Permutation is defined how

nPr = \frac{n!}{(n-r)!}

In our case n = 12 and r = 3

Thus

12P3 = \frac{12!}{(12-3)!}

12P3 = 1320

6 0
3 years ago
Can someone pls me help
olga nikolaevna [1]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ A standard deck of cards has 4 queens

4/52 = 0.0769

Therefore, your answer would be option C. 0.77

<h3><u>✽</u></h3>

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3 0
3 years ago
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Do,2 of Y is:<br> (5, 4)<br> (6,4)<br> (3/2,1)
kotegsom [21]

Answer:

(6,4)

Step-by-step explanation:

This question asks you to dilate by a factor of 2, and from the origin. Because it is from the origin, we can simply multiply the coordinates of Y by 2

3*2=6

2*2=4

so the result is 6,4

5 0
4 years ago
-3,-1,0,3 which pair of numbers has a sum of 0
kodGreya [7K]

In -3,-1,0,3 is -3 and 3 pair of numbers has a sum of 0.

To find the possible pair of integers in each section, we apply the notion of integers. If it's possible, choose any two variables from a set of numbers and look for relationships between them.

Positive and negative counting numbers, as well as zero, make up integers. Think about each pair of integers or numbers whose sum will be zero. Discover this particular pair. There are numerous ways to obtain two integers whose total is zero. However, the number must match the opposing sign exactly.

Given numbers are -3,-1,0,3

From the given sum of the numbers, -3 and 3  are zero.

-3+3=0

To learn more about integers refer the link:

brainly.com/question/12399107

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7 0
2 years ago
A research team conducted a study showing that approximately 25% of all businessmen who wear ties wear them so tightly that they
Sonbull [250]

Answer:A) 0.9866

Step-by-step explanation:

Probability of at least one tie is too tight is

Probability of tight tie 25/100

Probability of not a tight tie is 1-25/100=3/4

=1-(3/4)^15=0.9866

B)0.764

C)0.013

D)0.236

Method 2

This is binomial probability.

n=15 (number of businessmen

p=.25 (probability that a businessman wears the tie so tightly

A)

x = number of businessmen out of 15 who wears the tie so tightly

P( at least 1) = P( x >= 1) = 1-P(x=0)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P( at least 1) = 1- 0.013363 = 0.9866

B)

P(more than 2) = P( x > 2) = 1-P( x=0)-P(x=1)-P(x=2)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

P(x=1) = 15C1 (.25)^1 (.75)^14 = 0.066817

P(x=2) = 15C2 (.25)^2 (.75)^13 = 0.155907

1-P( x=0)-P(x=1)-P(x=2) = 1 - 0.013363 - 0.066817 - 0.155907 = 0.763912

C)

P(x=0) = 15C0 (.25)^0 (.75)^(15-0) = (0.75)^15 = 0.013363

D)

P( at least 13) = P(x=13)+P(x=14)+P(x=15)

P(x=13)= 15C13 (.25)^13 (.75)^2 = 0.000001

P(x=14)= 15C14 (.25)^14 (.75)^1 = 0.000000

P(x=15)= 15C15 (.25)^15 (.75)^0 = 0.000000

P(x=13)+P(x=14)+P(x=15) = .000001+.000000+.000000 = 0.000001

4 0
4 years ago
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