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3 years ago

11

Use the remainder Theorem and synthetic division to find p(3) for p(x) = x4 + x3 -x2 - 2x

1 answer:

maxonik [38]3 years ago

4 0

You do not need to use the remainder theorem to find p(3). Just plugin 3 where the x is located in

$x^4 + x^3 - x^2 - 2x$

$3^4 + 3^3 - 3^2 - 2(3) = 93$

Answer is a.

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Why is #2 the expression ln(2e)^3x equivalent to choice B?

motikmotik

Hello:
ln(2e^3x) =ln2+lne^3x
<span> =ln2 +3xlne
= ln2+3x .....lne=1
</span><span>choice B</span>

8 0

3 years ago

Unit 4 Test, Part 2: Congruence and Constructions<br> Help with my math please

lakkis [162]

Answer/Step-by-sep explanation:

1. Given:

∆NMK ≅ ∆TRP

$\overline{NM} = 20$

$\overline{MK} = 15$

$\overline{KN} = 25$

$\overline{TR} = 3x - 1$

a. To complete the congruent statement, thus: ∆MNK ≅ ∆RTP

b. The side that is congruent to $\overline{TR}$ is $\overline{NM}$ . Thus:

$\overline{TR}$ ≅ $\overline{NM}$

c. Since $\overline{TR}$ ≅ $\overline{NM}$ , therefore:

$\overline{TR} = \overline{NM}$

$3x - 1 = 20$ (substitution)

Add 1 to both sides

$3x = 20 + 1$

$3x = 21$

Divide both sides by 3

$x = \frac{21}{3}$

$x = 7$

2. a. Slope of LK = $\frac{rise}{run} = \frac{4}{3}$

Slope of LM = $\frac{rise}{run} = -\frac{3}{5}$

b. ✍️Length of LK is the distance between L(-7, 4) and (-4, 8):

$Lk = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$Lk = \sqrt{(-4 -(-7))^2 + (8 - 4)^2}$

$Lk = \sqrt{(3)^2 + (4)^2}$

$Lk = \sqrt{9 + 16}$

$Lk = \sqrt{25}$

$Lk = 5$

✍️Length of LM is the distance between L(-7, 4) and (-2, 1):

$LM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$LM = \sqrt{(-2 -(-7))^2 + (1 - 4)^2}$

$LM = \sqrt{(5)^2 + (-3)^2}$

$LM = \sqrt{25 + 9}$

$LM = \sqrt{34}$

$LM = 5.8$ (nearest tenth)

∆KLM is not an isosceles ∆ because it does not has two equal side lengths. This we can see because LK and LM are not equal.

Therefore, Anthony is incorrect. Am isosceles ∆ has two equal sides.

8 0

3 years ago

The value of 4c + 5g if c = 2 and g = 1.5

bixtya [17]

Answer:

15.5

Step-by-step explanation:

4c + 5g

= 4(2) + 5(1.5)

= 8 + 7.5

= 15.5

4 0

3 years ago

Help on this problem please!!

ExtremeBDS [4]

Answer:

points (8, 0) and (3, 0)

Step-by-step explanation:

Here we're being asked to find the roots of this quadratic equation.

Set f(x) = 3(x² - 11x + 24 = 0.

This factors into f(x) = 3(x - 8)(x - 3) = 0.

Then x - 8 = 0 and x - 3 = 0, yielding x = 8 and x = 3. These correspond to the points (8, 0) and (3, 0).

5 0

3 years ago

What is the area of an equilateral triangle that has a perimeter of 36 centimeters? Round to the nearest square centimeter.

Vika [28.1K]

Answer:

(a is size of side of triangle)

the perimeter of equilateral triangle =3a

or, 36=3a

Thus, a = 13cm

area of equilateral triangle

=√3/4*(a^2 )

=√3/4*(13^2)

=73cm^2

5 0

2 years ago